解答
因為 AC : BC = 2 : 5
假設 AC : BC = 2k : 5k
則 CM = k、CN = 5/2 k
MN = CM + CN = k + 5/2 k = 7/2 k = 21
=> k = 6
各段實際長度:
AC = 2k = 12
BC = 5k = 30
AM = MC = 12/2 = 6
CN = NB = 30/2 = 15
AN = 12 + 15 = 27
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因為 AC : BC = 2 : 5
假設 AC : BC = 2k : 5k
則 CM = k、CN = 5/2 k
MN = CM + CN = k + 5/2 k = 7/2 k = 21
=> k = 6
各段實際長度:
AC = 2k = 12
BC = 5k = 30
AM = MC = 12/2 = 6
CN = NB = 30/2 = 15
AN = 12 + 15 = 27
看了這個問題的人
也有瀏覽這些問題喔😉