=
f(a)
a+2+ = -25%0+5 = 23 lata=527
7. 某酵母菌在養分充足的條件下,經x日後的數量為f(x) = a·b*萬個,已知兩日後的數量為
(2)=36萬個,四日後的數量為(A)=81 萬個,求: f(x) = a. = 以一)
入 a b 36
(1)剛開始時的數量為(0) =
(b 萬個,3 (4) = n. 14、1-2
[ (bx. 6 a 9.236
(2)每經過一天其數量會增加
倍,
-3
+) B-
a = 36 x £ = 16
f(0) = ful -
8.94 f (x ) = log, x, g(x) = log, x, h(x)=logo24, kfx) = logo x AJ ME
bb =
f() = 36 f(3) = 54