Question

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*17.如上圖),已知BD:CD=3:2,P為AD上任一點,則△ABP面積:△ACP
面積=
3:2

Answer 1

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Mer

沒圖哦

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抱歉圖在這

Mer

△BDP:△CDP = BD:DC = 3:2(由P點做垂直BC線段，會發現同高)
同理，△ABD:△ACD = 3:2

令△BDP = 3x，△CDP = 2x
△ABD = 3y，△ACD = 2y

△ABP = 3y-3x = 3(y-x)
△ACP = 2y-2x = 2(y-x)
△ABP:△ACP = 3:2

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