Question

も

至急です🙇‍♂️

1.3kgの箱が上に35°引っ張られてる状況です。
箱が動き出す最小の摩擦力を見つける問題です。

解き方わかっていたつもりなんですが、全然解けなくて。
何な間違っているんでしょうか？
答えと解き方を教えて欲しいです。

A mass m₁ = 1.3 kg is pulled in the direction [E35°U] by a string. The
mass is at rest on a rough surface with the following friction
coefficients:
Ms = 0.6
μk = 0.4
8) If Ft = 4.00 N, what normal force acts on the mass?
9) If Ft = 4.00 N, what friction force acts on the mass?
10) If Ft = 6.00 N, what friction force acts on the mass?
11) If Ft = 6.00 N, what is the acceleration of the mass?
12) What is the smallest Ft that will get it to move?
10.44N
3,27 N
491N
Omis
3350
Ft

Flsin (34)
FN
Ffs FC COS (35)
Fg

Fismax = MS FN
=
(0.6). (mg(+ Ft-sin (35))
(0.6) (12.74- Ft (0.57))