Question

想搬到沒有數學的地方

想請問x=-1或1/3該怎麼回推|ax+k|=2呢？@@

將下列x的答案還原為x的絕對值方程式:
x的答案
還原成
x = 3 或-3
x = 5 或−5
x=6或-2
x=4或-1
x=6或4
x=-5或3
x=-1或
x=2或-1
x=-2 或4
14
x=-4
5
x=4或5
1
x=10或2
-7, 11
17
x=-3或x=-
|x-k=a
|x-k=a
|x-k=a
|2x-k|=a
|x-k=a
||x-k=a
|ax + k] = 2
lax + 1] = 3
||-x+k]=a
|ax-3|=b
|m-nx|1
|3x-k]=a
|rx+2]=s
lax+4=b
/axtb | = |ax|tb
幾何解法(畫圖):找中點、減中點、變成絕對值,最後再調整
·: | x-0 | = 3 = |x)=3
5
5
312=0 3
0
4
4
4
++
5 5
5
4
4
-H 3
$
44
+++
=>|x1=5
|x-01 =
|x-2] = 4
12x-k|-二
二12(x-)/x]2[
|x-|| = 5
=|zx-3| = 5
|x+1} = 4
1
|*(x-t)] = 2x1 =13x+1]=z
=x-1=
| = (ax+1)| = 3x | ² | = | = ax + ² | = 2²/1/2

Answer 1

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Terry

如圖

想搬到沒有數學的地方

喔喔！原來是這樣！謝謝你~~！