分段討論
(1) x ≧ 2
(x - 2) + 2(x + 1) = 5
3x = 5
x = 5/3,與前提不合
(2) -1 ≦ x ≦ 2
(-x + 2) + 2(x + 1) = 5
x = 1,在前提範圍內
(3) x ≦ -1
(-x + 2) + 2(-x - 1) = 5
3x = -5
=> x = -5/3,在前提範圍內
分段討論
(1) x ≧ 2
(x - 2) + 2(x + 1) = 5
3x = 5
x = 5/3,與前提不合
(2) -1 ≦ x ≦ 2
(-x + 2) + 2(x + 1) = 5
x = 1,在前提範圍內
(3) x ≦ -1
(-x + 2) + 2(-x - 1) = 5
3x = -5
=> x = -5/3,在前提範圍內
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