Question

郁欣

想問這樣解是對的嗎，謝謝🙏

yhw
例1 設ㄙ:2x-y-2=0與L:ax+4y+8=0兩直線的銳夾角為45°,則a之值
Y=2x-2
m = tan p
X-B = ±45°
tan (a-p) = tan (145)
² = -2mm)² = (± 1) '
tang=2
(2-M)² = (1+2m)²
[ (²-m) + (1+2m) ] [ (2-m) - (14²m)] = 0
(m+3) (-3m +1) = 0
m = - 3 = 1 =1/32