Question

訪客

我想了好久......

A:
Seption 2kh-2k + zk-nth-
O
3
ő
三、進階題
9. 試化簡lxml+3xn-1)+… + (2n-3) ×2 + (2n-1) x1.
zk (1-k + 2) -h-|
h
k21
[12k-11ch-k+1)
- 8 lkn uz k" + zk - htk-y. Å sku-2k + 3k-h-lo Ž -2k + 1/2h +37-(ht

無窮級數

Answer 1

Wonder

如