学年

質問の種類

英語 高校生

英語 高3 landmark 本文の内容です↓ 結局エルヴィス(犬)は微積分学を行っているのでしょうか? questionで、微積分学のような何かを行っていると書いてあったので、え、どっち?ってなりました。

Lesson 8 Animal Math Class No. Name (1) Birds do it. Dogs do it. Even salamanders do it. The ability to solve math problems is showing up in all sorts of unlikely creatures. A growing body of research suggests that nature a body of 1 probably discovered math long before people did. (2) Mathematician Tim Pennings, for instance, was at the beach when he discovered that his dog Elvis could do a type of math called calculus. "I would throw a ball into the water," Pennings says. "I noticed he'd run along the beach and then jump into the water and swim at an angle toward the ball." would (3) That's a good strategy. Swimming is slow compared with running, so swimming all the way to the ball would take longer even if the route is more direct. On the other hand, running along the beach adds to the total distance Elvis must go to get to the ball. The best bet is a - increase compromise between the two-running a certain distance along the beach before plunging into the water. (4) Pennings wondered if Elvis was instinctively taking the fastest possible route to the ball. First, he measured how fast Elvis runs and swims. Next, he threw a tennis ball into the water and let the dog go. Then he measured how far the dog ran and swam again and again. Pennings had 35 sets of measurements. He went home and did some calculations, using calculus to find the fastest route. Pennings says, "I figured out that where Elvis jumps in is -solve pretty much perfect. He naturally knows the right spot to jump in." (5) It took the grown man about an hour to come up with the same solution(that the 3-year- old dog figured out in a fraction of a second) But is the dog really doing the math? "Elvis is doing calculus in the sense that he somehow knows how to find the minimum time to get to the ball," Pennings says. (6) Pennings suspects that other creatures have naturally learned the most efficient ways to do things over millions of years of evolution. (7) Studying math skills in dogs to understand math in people might not be such a far- fetched idea. In fact, some research is showing that babies and animals actually have a lot in common when it comes to numbers. **.*

回答募集中 回答数: 0
数学 高校生

赤く丸をしたbの問題で解答の方に二階微分した後の式がなぜ(-1/4)(-1/4)(H-27)になるのか分かりません。教えてください🙇‍♀️

QA At time t = 0, a boiled potato is taken from a pot on a stove and left to cool in a kitchen. The internal temperature of the potato is 91 degrees Celsius (°C) at time t = 0, and the internal temperature of the potato is greater than 27°C for all times t > 0. The internal temperature of the potato at time t minutes can be modeled by the function H that satisfies the differential equation dH (H- (H-27), where H(t) is dt measured in degrees Celsius and H(0) = 91. (a) Write an equation for the line tangent to the graph of Hat t = 0. Use this equation to approximate the internal temperature of the potato at time t = 3. (b) Use 2017 APⓇ CALCULUS AB FREE-RESPONSE QUESTIONS (a) dH d²H dt² to determine whether your answer in part (a) is an underestimate or an overestimate of the internal temperature of the potato at time t = 3. (c) For t < 10, an alternate model for the internal temperature of the potato at time 7 minutes is the function -= − (G - 27)²/3, where G(t) is measured in degrees Celsius dG G that satisfies the differential equation dt and G(0) = 91. Find an expression for G(t). Based on this model, what is the internal temperature of the potato at time t = 3 ? 564 at (21-27) - == 2-16 To = - = (H(3)-27) 4 -64 = HB)-27 -37 = H (3) (b) _d²fi © 2017 The College Board. Visit the College Board on the Web: www.collegeboard.org. GO ON TO THE NEXT P

回答募集中 回答数: 0
数学 大学生・専門学校生・社会人

多様体の接空間に関する基底定理の証明です。g(q)=∫〜と定義した関数を微積分学の基本定理を用いながら変形してg(q)=g(0)+∑gᵢuⁱと導出するのですが、これがうまくいきません。 自分は、g(q)の式をまず両辺tで微分して、次に両辺uⁱで積分して、最後に両辺tで積分... 続きを読む

12. Theorem.If{ = (x', , x") is a coordinate system in M at p, then its coordinate vectors d, lp, …… 0,l, forma basis for the tangent space T,(M); and D= E(x) 。 i=1 for all ve T(M). Proof. By the preceding remarks we can work solely on the coordinate neighborhood of G. Since u(c) = Othere is no loss of generality in assuming ど(p) = 0eR". Shrinking W if necessary gives E(W) = {qe R":|q| < } for some 8. Ifg is a smooth function on E(W) then for each 1 <isndefine og (tq) dt du g(9) = for all qe {(W). It follows using the fundamental theorem of calculus that g= g(0) + E&,u' on (W). Thus if fe &(M), setting g = f。' yields f= f(P) + Ex on U. Applying d/ax' gives f(p) = (f /0x)(P). Thus applying the tangent vector e to the formula gives (f) = 0+ E(x'(p) + E Ap)u(x) = E(Px). ず ax Since this holds for all f e &(M), the tangent vectors v and Z Ux') d,l, are equal. It remains to show that the coordinate vectors are linearly independent. But if ) a, o.l, = 0, then application to x' yields dxi 0=24 (P) = 2q d」= 4. In particular the (vector space) dimension of T,(M) is the same as the dimension of M.

未解決 回答数: 1