A
気体
(1)
【課題2】
29 °C
P: 610 x 104 Pa
VA! 10 L
Calts (7°0/1^2)
0₂ 2
-A&B GHS + 50₂ → 200₂ + 4H₂O
27℃°C
(2) 127°C
P = ?
P = ?
V = 5.0 L
V = 5.0L
(1) ボイルの法則より
PAVL
C3HP 253X104 Pa x ho
=
B 0₂ (024)
27°C
P:/,20 x 10 Pa
VB MOL
1.2 x 105 Pa x 4.0
= 1₁2 × 104 Pa ±3.56×/0³ = 3,39 x 10¹
48 × 105
2 0.96 x 105 = 9₁6 × 104 Pa +3.56x/0³
2.69 x 101
PA + PB = Paty P = 3.37 10¹ 2,69 * 10¹
= 7.1x/0² Pa
2
9.30
2169
7.88
1