Question

書理

這是一題單純的R與C並聯，Z是並聯後的阻抗，請問Rx和Cx怎麼推導

(b) Z, remains the same as in Eq. (9.15.4) but R, and X, are in
parallel. Assuming an RC parallel combination,
Zx = (5.993-j1.356) MQ
1
RK
Rx (1-ju
= Rx ||
=
jwCx
1 + jwRxCx
i+w Rx
5.993
R₁ =
By equating the real and imaginary parts, we obtain
Real(Z)² + Imag(Zx)² _ 5.993² + 1.356²
Real(ZX)
Re Zx
= 6.3 M2
5.993
Imag(Z)
Rx = 5.993² +1.3562
5.993
C₁ = =
[Real(Z)² + Imag(Z)²]
Cx = -
-1356
2Tu₂k[5.993)² +
-1.356
2z(2000)(5.9172+1.356²)
=
= 2.852 μF