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31.
AE : BF = 3:2
AE : ED = BF : FG = 2:1
所以ED = 3/2,AD = 9/2
AD : BC = (9/2):5 = 9:10
34.
DFCE是平行四邊形
所以DE = FC = x
8:20 = x : (24+x)
27.
AH = 9/5
BA : BC = AD : DC = 3:4
AD = (3/7)AC = 15/7
DH = (15/7)-(9/5) = 12/35
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國三數學相似形
求解
✨ ベストアンサー ✨
31.
AE : BF = 3:2
AE : ED = BF : FG = 2:1
所以ED = 3/2,AD = 9/2
AD : BC = (9/2):5 = 9:10
34.
DFCE是平行四邊形
所以DE = FC = x
8:20 = x : (24+x)
27.
AH = 9/5
BA : BC = AD : DC = 3:4
AD = (3/7)AC = 15/7
DH = (15/7)-(9/5) = 12/35
謝謝你!
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33.
DH : DB = GH : AB
2:5 = GH : 12,GH = 24/5 = 4.8