Question

昍奕

求解

擻
y=2
二次函數y=a(x+h)2−k的圖形與x軸交於A、B兩點,與y軸交於(0,-3),若
AB=b,且當x=-1時有最大值3,則a+b+h+k=
(√2.2)
-104√2
-6√2-1-3
-8+√2
A
1-2 = 3/1/
1(0--3)
y = a (x + 1)² +3
(X+1)*
=
-3
Sy=-6(x+hJ²³-k
3 = -6 (-1th) ² - K
1-3 = -6 (0th) ² - K

二次函數

Answer 1

Ny-Ålesund

當 x = -1 時有最大值 3
=> 頂點 (-1, 3) 開口向下

假設方程式 y = a(x + 1)^2 + 3
通過 (0, -3)
=> a(0 + 1)^2 + 3 = -3
a + 3 = -3
=> a = -6
=> y = -6(x + 1)^2 + 3

與 x 軸交點 => 令 y = 0