Answers

x²+y²+2kx-ky+(k-1)=0
(x+k)²+(y-k/2)²=-k+1+k²+k²/4=5k²/4-k+1>0
r²=5k²/4-k+1>0
=5(k/2-1/5)²+4/5>0
當k=2/5時,r² min=4/5
所求=4/5π

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