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問題的種類

英文 高中

想請問第16格 詳解說是倒裝,請問倒裝句要怎麼分辨,然後為什麼這邊的倒裝要加as ( 我文法很弱 非常感謝解答😭❤️😖)

第16.至20.題為題組 The origin of the well-loved stuffed toy teddy bear can be traced back to the story of Theodore Roosevelt, the president of the US from 1901 to 1909. In 1902, as a devoted hunter, Theodore Roosevelt 16. he loved hunting, he failed to went on a trip of bear hunting with his assistant and staff. Much find a single prey that day. One of Roosevelt's assistants tied a baby bear to a willow tree and suggested that he shoot it. Roosevelt refused and thought that it was cruel to shoot a defenseless animal. Little 17. the president know that his actions would cause the creation of a world-famous toy. The story soon spread to every corner in the country. Newspapers around the country kept recounting the story of Theodore Roosevelt and the bear. An owner of a sweet shop heard the story and was deeply impressed by Roosevelt's 18. . In order to express his admiration for the president, he had an idea of creating a toy bear 19. Theodore Roosevelt, or Teddy. These stuffed toys, now known as teddy bears, sold like hot cakes. Women and children alike carried a teddy bear with them no matter where they went. Interestingly, Theodore Roosevelt himself, while 20. for his second term in office in 1904, also used the teddy bear as his mascot. Nowadays, the teddy bear remains one of the most popular gifts all over the world.

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數學 高中

請問12題有更快的解法嗎🙏🏻

單元7 圓與直線的關係 55 二、素養混合題(共20分) 第11至12題為題組 星空橋上有一個雙半圓的藝術裝飾建築,為了要支撐裝飾品的重量,在上頭加裝了許多 條纜繩垂直橋面,設O點為坐標平面上的原點,且E點距離原點4公尺,纜繩BE=4/15公 尺,小半圓的半徑為大半圓半徑的。 1 其中為大半圓的圓心,G為小半圓的圓心。 4 UNTS (460) L F Q E DMI GK N(2.0) 11. 為加強藝術建築的穩固性,計劃在雙圓上各加裝一條纜繩,且兩條纜繩需垂直橋面, 其中一條經評估要加裝在O點左方8公尺處(CF),另一條加裝在G點左方2公尺處 (HI),則需要準備 18 公尺的纜繩。(無條件進位,取至整數位)(填充 題,10分) 12.聖誕節即將來臨,星空橋上有燈光秀,光源都從點(-16,0)與點N(24,0)發射。在聖誕 節當日有特別秀,驚喜安排的位置位在直線:「通過ㄥ點且與小半圆相切的直線」與 直線L:「通過點且與大半圆相切的直線」的交點位置上,請問驚喜出現的坐標位置 為何?(非選擇題,10分) 10. (106. ((2)9 CB:116+240 =√√256=16=rk CE- & 44:48+ +1=25 105=√√300 +18 ED: 4= mix+16) EB: 4= mex-24) mxx-4+16:0 mx-4-4-0 : :4 = 16 Jm²+1 361=441 |x4|= 16√271 1296m²:16m²+16 {√5x-204-- 165 N5x=-1615 bis 1280=-16 17√5x-54=48√5 S = +6√5+32015 2015x-404=-325 x=16√x. (205x-54:48.8 9 2m² = 10 41 (76 4548015 9 168555 y= 45 425 576143567256 30m²:256 m² = 256 4 4 8 4 405

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