請問這幾題怎麼解？ 拜託🙏

1. 請以方塊圖簡化方法(聚合點左移、分歧點右移、回授方塊圖公式求轉移函數),求 C(s) 下圖所示方塊圖系統的 轉移函數。 R(s) R(s). C(s) C(s) 2. 請繪出上圖(題1.)之訊號流程圖,並利用梅森增益公式求 轉移函數。 R(s) 3. 已知某線性非時變系統的微分方程式如下,其中u(t)與y(t)分別表輸入及輸 出,試求轉移函數。 dt³ (1) d³y(t) + 5 d² y(t) + 4 dy(t) dr² dt + y(t) = )=2. +3u(t) du(t) dt dt² (2) d²¸y (1) + 3 dy (t) + 2 y (t) + √ " y(t)dt=u(t) dt Y(s) a 4. 某控制系統的方塊圖如下所示,若其具有轉移函數為 R(s) S² + bs + a 則a 及b 之值為何? 4 R(s). Y(s) s+1 5. 求下題的輸出y(t) = ? S 若8(1) 線性 -h(1)=e-31(120) 非時變 線性 則 3e-StuG (1) - -y(1)之值 非時變

微積分 我想問第（3）題

1. 下列各題:求f(x)在 I 上的所有奇異點,並決定f(x)遞增、遞減的範圍。最後, 作f(x) 值的走勢圖,指出產生相對極值以及絕對極值的地方。 (1) f(x)=x²-3x+6, I = [-2, 2] (2) f(x)=x²-6x²+9x-6,I= [0, 5] (3) f(x)=x²e-*,I=R (4) f(x)=-x°+9x²-15x+10,I= [0, 6]

求解

Chrome 檔案 Sylves Scores M Gmail ▸YouTube | 地圖 Pearson eText Purchase Options Study Area User Settings Course Home Ghe binding energy of a two-par X + openvellum.ecollege.com/course.html?courseld=17667848&OpenVellumHMAC=9c8d5dd7baa0c70ec3a75db4e52f2d39#10001 Document Sharing Course Tools 檢視 歷史記錄 書籤 設定檔 分頁 視窗 說明 單 > 翻譯 The position of a 280 g object is given (in meters) by x = 5.1 t³ - 8.0 t²-44 t, where t is in seconds. https://session.masteringphysics.com/myct/itemView?assignment ProblemID=176946106 10月 13 Part A tv Determine the net rate of work done on this object at t = 2.0s. Express your answer using two significant figures. Pt 2.0s= = Submit Part B VAΣO Pt=4.18= = Request Answer Determine the net rate of work done on this object at t = 4.1s. Express your answer using two significant figures. VAE P Pearson ? 1999+ ? W Caright © 2022 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy. Permissions Contact Us | W G3 ✩ 10月13日 週四 上午 12:38 I Constants 更新

求解

Chrome 檔案 M Gmail 3 My Courses Course Home Syllabus Scores YouTube Pearson eText Study Area Purchase Options User Settings Course Home X Ghe binding energy of a two-par x + openvellum.ecollege.com/course.html?courseld=17667848&OpenVellumHMAC-9c8d5dd7baa0c70ec3a75db4e52f2d39#10001 Document Sharing Course Tools 單 檢視 歷史記錄 書籤 設定檔 分頁 視窗 說明 地圖 > 翻譯 <L.8 Problem 8.51 Part A W = Submit VAE Provide Feedback How much work would be required to move a satellite of mass m from a circular orbit of radius r₁= 2re about the Earth to another circular orbit of radius r2 = 3rE? (rE is the radius of the Earth.) Express your answer in terms of the variable m and constants rE, ME, and G. Request Answer https://session.masteringphysics.com/myct/itemView?assignment ProblemID=176946298 10月 13 tv ? 10月13日 週四 上午12:37 - 999+ ■ 8 of 10 更新: Constants Next >

求解

Chrome 檔案 M Gmail 3 My Courses Course Home Syllabus Scores YouTube Pearson eText Study Area Purchase Options Course Home User Settings Document Sharing Course Tools 單 openvellum.ecollege.com/course.html?courseld=17667848&OpenVellumHMAC=9c8d5dd7baa0c70ec3a75db4e52f2d39#10001 檢視 歷史記錄 書籤 設定檔 分頁 視窗 說明 地圖 > 翻譯 X Ghe binding energy of a two-par x + <L.8 Problem 8.99 A satellite is in an elliptic orbit around the Earth. Its speed at the perigee A is 8526 m/s (Figure 1). Figure 16,460 km B 8230 km 8230 km 10月 13 A 1 of 1 14.255 km tv UB = Use conservation of energy to determine its speed at B. The radius of the Earth is 6380 km. Express your answer in meters per second. Submit Part B VC = VAΣ Submit Request Answer Use conservation of energy to determine the speed at the apogee C. Express your answer in meters per second. VAE Request Answer ? 1999+ m/s ? G m/s 10月13日 週四 上午12:37 ■ 10 of 10 Constants 更新

求救

Chrome 檔案 M Gmail Course Home Syllabus Scores YouTube Pearson eText Study Area Purchase Options Course Home User Settings Document Sharing Course Tools 單 openvellum.ecollege.com/course.html?courseld=17667848&OpenVellumHMAC=9c8d5dd7baa0c70ec3a75db4e52f2d39# 10001 檢視 歷史記錄 書籤 設定檔 分頁 視窗 說明 地圖 > 翻譯 X Ghe binding energy of a two-par x + <L.8 Problem 8.75 The binding energy of a two-particle system is defined as the energy required to separate the two particles from their state of lowest energy to r= ∞o. The potential energy of the two atoms in a diatomic (two-atom) molecule can be written b U(r) = − 6 +12, where r is the distance between the two atoms and a and b are positive constants. 10月 13 Part A Determine the binding energy for this molecule. Express your answer in terms of the variables a and b. Ebind= Submit Provide Feedback VAEO tv JA xa Xb b √x x x X Incorrect; Try Again; 3 attempts remaining Previous Answers Request Answer 1999+ C |X| ? X.10n 10月13日 週四 上午12:33 I 9 of 10 Constants 更新 Next >

請教我這一題這題有點難

5. O 根據表1~表2, (1)請求出管制圖中的R、又 (2)請求出管制上、下界與中心線 (3) 繪出X管制圖 表1 電腦製造過程之觀測值 組別 數據 1 6 10 2 10 3 7 10 4 8 5 9 10 6 12 10 7 16 10 8 7 10 9 9 10 15 16 10 N00 TTTT 3489111571 6 15 11 5 13 13 10 库116116718181 OO oww ON OL 9 NO Olo 4 12 13 WNI 表2 建立計量值管制圖因子 ** 反三均售重 OS R全拒害 警告三 =美的三表 89 三 B1 B2 B3 B4 d2 d3 D1 D2 D3 D4 #min 1.843 0 3.267 1.128 0.853 0 3.686 3.257 A A1 A2 C2 2.121 3.760 1.880 0.5642 3 1.732 2.394 1.023 0.7236 1.500 1.890 0.729 0.7979 1.342 1.596 0.577 0.8407 1.858 0 2.568 1.693 0.888 0 4.358 2.575 loooo 0 1.808 0 2.266 2.059 0.880 4.698 2.282 O 1.756 2.089 2.326 0.864 4.918 2.115 1.225 1.4100483 0.8586 0.026 1.711 0.030 1.970 2.534 0.848 5.078 0 2.004 7 1.134 1.277 0.419 0.8882 0.105 1.672 0.118 1.882 2.704 0.833 0.205 5.203 0.076 1.924 8 1.061 1.175 0.373 0.9027 0.167 1.638 0.185 1.815 2.847 0.820 0.387 5.307 0.136 1.864 9 1.000 1.094 0.337 0.9139 0.210 1.609 0.239 1.761 2.970 0.808 0.546 5.394 0.184 1.816 10 0.949 1.028 0.308 0.9227 0.262 1.584 0.284 1.716 3.078 0.797 0.687 5.469 0.233 1.777 110.905 0.973 0.285 0.9300 0.299 1.561 0.321 1.679 3.173 0.787 0.8125.534 0.256 1.744 120.866 0.925 0.266 0.9359 0.331 1.5410.3541.645 3.258 0.778 0.924 5.592 0.284 1.716 13 0.832 0.884 0.249 0.9410 0.359 1.523 0.382 1.618 3.336 0.770 1.026 5.646 0.308 1.692 14 0.802 0.848 0.285 0.9453 0.3841.507 0.405 1.594 3.407 0.762 1.121 5.693 0.329 1.671 150.775 0.816 0.223 0.9490 0.406 1492 0.428 1.572 3.472 0.755 1.207 5.737 0.348 1.652 16 0.750 0.788 0.2120.9523 0.4271.478 0.448 1.552 3.532 0.749 1.285 5.779 0.364 1.636 170.728 0.762 0.203 0.9551 0.4451.465 0.465 1.5343.588 0.743 1.359 5.817 0.3791.621 180.707 0.738 0.1940.9576 0.461 1.454 0.4821.5183.640 10.738 1.426 5.854 0.392 1.606 190.688 0.717 0.1870.9599 0.4771.443 0.4971503 2.689 0.733 1.49 5.888 0.404 1.596 20 0.671 0.697 0.1800.9619 0.491 1.433 0.510 1.490 3735 0.729 1548 5.922 0.414 1.586 21 0.655 0.679 0.173 0.9638 0.504 1.424 0.523 1.477 3.778 0.724 1.605 5.950 0.425 1.575 22 0.6400 0.662 0.167 0.9655 0.516 1.415 0.534 1.456 3.819 0.720 1.659 5979 0.434 1.586 23 0.525 0.647 0.162 0.9070 0.527 1.427 0.545 1.455 3.885 0.716 1710 6.006 0.443 1.557 24 0.612 0.632 0.157 0.9584 0.538 1.399 0.5551445 3.895 0.712 17596.031 0.452 1.548 25 0.500 0.9190.153 0.9696 0.548 1.392 0.5651.435 3.931 0.709 1 904 6.058 0.459 1.541

大學水文學 有人可以幫忙解答嗎？ 謝謝

| | b3 bi b2 di d3 d6 d5 (1)有一河川断面,呈測流速位置資料如下表,流速儀公式為V(m/s) =0.3 +0.2N(轉/s),試以平均 斷面法推算該斷面之流量Q(cms)? (20%) *十年到小数第2位 星期 E N J Vi KÉ 布 bi(m) di(m) (禁 (m/s) (m/s) Ai (m2) Qi ( cms) 0 0.00 1 1.2. 0.5 b4 b5 b6 b7 2 更 2. 0.5 1 1.5 0.8 4 3 1.8 0.8 5 2 0.5 6 0.2 0.00 å åt Q (cms) (2)有一集水區 400 公頃,其連續兩場各4hr (兩組圖如右圖)之親測出口流 美如下表蓋扣除其流会到中直接庭DR日,並推三日平均入文 4 (cm/hr)? (20%) (hr) 12 意三 (cms) 4 3 NN NJ | 2 24 Rim 2 2:03 下午yrp-wysr-ctu

有人知道這個程式碼要怎麼寫嗎

PHOTO tomorrow # E[Python ladb8a1fb88a40d5bf8df59c5d3805@c_4]$ py 第1個星期 25-5.重數10.00 個程式,記錄周的動物園遊園人數,如下表。 9 for $1]LÈS. 一周的资料 2.取出每天的遊客數 星星 星星 周星期 星星期 期期期期 人次目 面 ply 1 50 10 14 7 25 30 70 第2 30 24 14 9 87 63 87 63 25 3 第 13 # 100 52 82 89 36 78 22

求好心人解答 感謝

科自名稱:綜合化學【材光系前贍應用材料碩士班甲組】 若號 :487003 販本科日依簡章規定「不可以』」佑用計算機(選擇題) 共4頁第1頁 耿還題 , 每題5分 , 總分 100分, 上 Forwoe RuX(coLa] complex, whatare the ineducible representation for experimentaliy observed IR strstching bands? 人 是人 5 1 my 和 列+朮 加說說 放廬詭ee 只下人生信和有生宮 共計 昌証只 eey (090Bo (Ba 0OBwe 四Bw 紀 Whataethe bonqordersof[Mo,(sooj7 5 2 @3 390) @4 把 Howmany microstates dose O atom hasin (1sj02sj(2p) configuration ? (9 1 (90915018 2 反 Whatisthe ligand-feld stabilization energy of[Fe(CN)dJr? 03125A (0295 (06 (0D35A 215 反 Whichofthe following step is included in the Fiseher-Tropsch process? (A) Insertion via metallocycJbutane (B) SplittingoftheC- obond (CO _c-Nbondfomation (D) 1,2.insertion 咒 stememts eoneeming systematie erors random enors and gross enors計 Bedeeeeted by Studentetestfortwoindependentsamples zed by averaging overalarge number ofobservatons by Fatest for two independcnt sarnples systematie erors. emorsinanEDTA Gitatoninclude nouton mistakes and geomeeming ttationik INCORRECT? daneutalizadon ttaton, whichcan beusedlo aahembe reduetion polental @f he analyte