這題有沒有可能只用反函數就可以解出來⋯ 為啥算不出答案，ㄚ。

Assignment (part I) (page 50) *2-8. Two forces are applied at the end of a screw eye in order to remove the post. Determine the angle 0 (0° ≤ 0 ≤ 90°) and the magnitude of force F so that the resultant force acting on the post is directed vertically upward and has a magnitude of 750 N. 30° 500 N 2025/2/25 CHIANG Yu-Chou 33

感覺這題要用反函數

Finding Values In Exercises 28-30, find f-1(a) for the function f and real number a. Function 30. f(x) = x³ - Real Number 4 x > 0 a = 6 X

第五題是因為沒除2被扣分嗎

X = 109. (Y+ JY²41) =>2²=Y+SY²³1 5²(x) = 2^²=√²+1 4. (10%) 證明 f(x)=log2 (2+VⅠ? + 1) 為奇函數,並求其反函數 5. (10%)寫出三角函數積化和差(三條) 公式。 (1) sin (α(+B) + sin(2-³)=2 sinx cUSB (05(x-B)-(056d+ ° (2) (05 (α-B) + CO₂(X+B) =Zcosx.cosB³ = 2 sind sing (3) 6. (10%) 將 sin(cos a + tan-y) 化簡為 工, y 的(不含三角函數之)表示式,其中 -1 ≤x≤1, y ∈ P (b) (5%) sin(tan-¹x) (c) (5%) sin (2 tan-¹ x) (d) (5%) sin(cos-¹2) 1 7. (10%) 證明 2 tan' X 6. sin (d+B) = sind cosB+ cosa sin B ()() + (x)( 2x X41 = COS x²-1 tt x2+10 面 Jity AUF-X² Thoxe Storipy THIN x -10

想問第10題的dy/dx要怎麼求？看得很亂@@

a+b+C > Yabc | 9. 若 a, b, c > 0,試證 3 10. 驗證 y = log(x + V1 +x)爲單調,從而求其反函數

求解釋這一題 看不太懂😭

例題:【反函數】 若f(x) = x²,f:[0,3]→[09],求 f(x)的反函數。 2: To9]→{0.3] 解: f(x) = x 在 [0,3]上為1-1 函數,取f'(x) = x,則有 f(f'(x)) = (√x)} = =x, ∀x∈[0,1] 345 S' (f(x))=√x² = =x,∀x∈[0,0],故f(x) 的反函數為」。 f(x)=xx 2:57/9:52 y X

第四題求解！不知道要怎麼證明反函數 看了答案還是不懂🥹 Ans: f。g=x and g。f=x

1 4. Show that the functions f(x) = ²x-1 and g(x) = = + ln√√x are inverse functions. 2 D' 1 dy .... 1:41. 2-x .2 1..3 1 2

求解🫠🫠🫠🫠

f(x)=e* + lnx • ✯ (ƒ˜¹)'(e) = ? 9

想請問這題的(b)怎麼解！

Question 3: If f(x)=x³+3x+1, evaluate (a) f'(2) and (b) (-¹)(15). Sele

請問如何找這個函數的反函數?

I to Xs (x) 4 XE-9

求3 4 曲線長度

((( 本即肖恩/// = - = = = > 1 13.4.9. 求曲線在指定範圍中的長度 (1) y=xi, x = 0, x = 1 (c0=1 (2) y = x3, x = 0, x=1 (3) y = e", x = 0, x = 1 (4) y = 1, 1 = -1, 1 = 1 y = , x=1 (Hint: (1) (2)互為反函數.) - ( - et te- x 2 1 C 1 9