看不懂老師的算式 有人能幫我拆解步驟解釋一下嗎 或是另外寫易懂的算式過程 拜偷

A sample containing 25.14g of neutral salts, glucose and a sodium carbonate/bicarbonate buffer was dissolved in 100 ml of water. A 25 ml aliquot of the resultant solution required 20.35 ml of 0.0987 M HCl when titrated to the PP end-point. A second 25 ml aliquot was titrated to the MO end-point and required 56.75 ml of the acid. Calculate the percentage of Na2CO3 (molecular weight 106) and NaHCO3 (molecular weight 84) in the sample. 含有25.14克中性鹽、葡萄糖和碳酸鈉/碳酸氫鈉的樣品將緩衝液溶解在100ml水中。需要25毫升等份所得溶液滴定至PP終點 時,使用20.35ml 0.0987 M HCl。第二份25毫升等分樣本是滴定至MO終點,需要56.75ml酸。計算百分比樣品中的Na2C03 (分子量106)和NaHCO3(分子量84) 39

求解10xBSA怎麼解？

Exercise 1 • A5 kb plasmid DNA has two Bam HI sites. You would like to use this enzyme to digest 5ug of this DNA. How would you do? (DNA concentration: 2 mg/ml) Bam HI concentration: 20000 U/ml Unit definition of Bam HI: 1 unit enzyme can completely digest 1 ug of lambda DNA at 37 °C in 1 hour. (lambda DNA has 48500 bp and 5 Bam HI sites) The reaction needs supplement with 100 ug/ml bovine serum albumin (BSA, 10x concentration) • Calculate the volume of all ingredients and setup the reaction table.

求分析化學解答

Derive the expression of concentration-based equilibrium constant (K') in terms of thermodynamic equilibrium constant (K) and the activity coefficients (y;) of the participating species for the dissociation reaction in a supersaturated aqueous solution of silver arsenate, AgzAsO4(s).

想問問看大家這題普化😭

Crjticat Thinking ) The text states that “the pKa of 和e weak acid selected for the puffer shoujd be as close as pos- sible to the desired pH.”What 1 the pK, is not close to the desired PH? What is the problem with choosing such a weak acid used um 出e buffer?

普化問題 麻煩大家ㄌ🥺🥺

Criticat Thinking ) The text states at “the pKa ot 仙e weak acid selected for the puffer shoujd be as close as pos- siple to the desired pH.” What 1 出epKa is not close to the deslired PH? What is the problem with choosing such a weak acid used 症 出e buffer?