微積分求解

8. [0/8 Points] Consider the following limit. DETAILS lim Ax-0+ lim Ax-0+ Submit Answer 8 X + Ax Ax Simplify the rational expression as much as possible. 8 x(x + Ax) X 8 X PREVIOUS ANSWERS X Evaluate the one-sided limit. (If an answer does not exist, enter DNE.) DNE LARCALC12M 1.4.029.EP.

請問這題要怎麼算～

1 89. Let f be a function such that f'(x): If 1 + x² 0₁5 2 LIFE AND Qurbliet 1 + x² dig(x) = f(2x + 1), what is g'(x)?sup inslissxs) =

想問第4題畫線處 分母(tan²x)-1 =(sin²x/cos²x)-1 =(sin²x-cos²x)/cos²x 為什麼把1/cos²x移到分子以後 分母不是sin²x-cos²x ? 感謝！

x² Example 4 Find lim x 0 sec X 1 SOLUTION The evaluation of this limit requires a little imagination. Since both the numerator and denominator tend to zero as x tends to zero, it is not clear what happens to the fraction. However, we can rewrite the fraction in a more amenable form by multiplying both numerator and denominator by sec x + 1. x2 x² sec x 1 lim x-0 secx 1 - = = x2 sec x 1 - x² (secx + 1) sec² x 1 lim (sin x-0 sin x sec x + 1 sec x + 1) - = Since each of these factors has a limit as x tends to 0, the fraction we began with has a limit: = x² (secx + 1) tan² x - 1 x² cos²x(secx + 1) sin² X 2 (*) ² (cos²x)(secx + 1). 2 ·lim cos²x lim (secx + 1) = (1)(1)(2) = 2. x→0 x ●

求解第24題

t (a), explain wh 2+x-6 x-2 lim (x + 3) imit, if it exists. 12. lim x² - 4x x-1 x²-3x - 4 14. lim 2x² + 3x + 1 2 x-1 X² 2x - 3 16. lim 18. lim h→0 20. lim X→-1 22. lim u-2 24. lim t-0 (2 + h) - 8 h 3x - 4 28. lim h→0 x² + 2x + 1 .4. - 1 26. lim x--4 (1 t 4u + 1 u - 2 3 t² + t x²+9-5 x + 4 1 (x + h)² h 1 X Illustrate tion of th 33. If 4x 34. If 2x - 35. Prove 36. Prove 37-42= explain 37. lim 39. 41. 43

第一行是題目 第二行是給的詳解 我從第一步就不懂 為什麼要假設成L?🤨 後面也看不懂QWQ

Question Limit. 4. Find the humber c such that lim 3x²+CX+c+3 X-7-2 X²+X-2 exists and evaluate this limit. lim A = Suppose X+2+x²+x-2² = L. We have that lim (3x+exto+ 3) = lim (2xxxx112 x (x²7x²)) X7-2 x=-2 X+X-2 3x²+x+c+3 = ( Lim Xxx-9²³) x (&im₂ (X+X-2)) = Lx0=0 X-7-2 => 3x(-2)² + cx (-2) + C+3=15-C=O=> C=15

請問第41題這種類型的題目要怎麼解🙏🙏

41-44 Use implicit differentiation to find az/ax and az/ay. .2 41. x² + 2y² + 3z² = 1 (42. x² - y² + z² – 2z = 4 (43) e² = xyz 44.) yz + x ln y = z²

請問第六和第十題如何計算？ 大學微積分 Integration by parts

S. cite the formula for integration by parts. plain how you would choose u and du when using the egration by parts formula. Illustrate your answer with ar Exercises es 1-28, find each indefinite integral. 32. x dx -X 35. F. et dx - tc th - x)² dx 36. F. tc 1) ex dx th - 2. { xe* dx 4. S 6xe* | * dx 6. [(e-* + x) dx 8. S (x – 3)e% de 10. S x(x + 4)-2 dx . 14. S x? In 2x dx 16. Vx In x dx + 1)-32 dx 37. F f f E-5 dx 12. 3x V2x + 3 dx 38. F f f 2x dx 39. V af x dx 1

離散數學第二章 邏輯的基本原則 請問這題的b怎麼算

19. Provide the steps and reasons, as in Exercise 18, to establish the following logical equivalences. a) p V [p ^ (p V q)] p lorer v b) p va v (p^^r) A p Vavr c) [(-pv-q) → (p^q^r)] paq 20. Şimplify each of the networks shown in Fig. 3.

離散數學第二章 請問這題怎麼寫～

13. If statement q has the truth value 1, determine all truth value assignments for the primitive statements, p, r, and s for which the truth value of the statement (q + V r) 4-s] A[ → (719)] 13 O o - und is 1. vry n shit zung ->

請問這題怎麼解🙏🙏

15) J Hit dx VX+1 + 5X