解答
假設邊長分別為 a、b
依題意:
4a + 4b = 100
=> a + b = 25
=> b = 25 - a
a^2 + b^2 = 325
=> a^2 + (25 -a)^2 = 325
2*a^2 -50a +625 = 325
a^2 -25a +150 = 0
(a -10)(a -15) = 0
a = 10 or 15
=> b = 15 or 10
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假設邊長分別為 a、b
依題意:
4a + 4b = 100
=> a + b = 25
=> b = 25 - a
a^2 + b^2 = 325
=> a^2 + (25 -a)^2 = 325
2*a^2 -50a +625 = 325
a^2 -25a +150 = 0
(a -10)(a -15) = 0
a = 10 or 15
=> b = 15 or 10
看了這個問題的人
也有瀏覽這些問題喔😉