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解答

AB中點座標((a+b)/2, 2)
2[(a+b)/2] + 2 = 4
a + b = 2⋯①
令直線AB:x - 2y = c
a - 2 = c⋯②
b - 6 = c⋯③
②-③ a - b = -4⋯④
①+④ 2a = -2
a = -1
b = 3
2a + b = 1

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