Mer 8個月以前 做 EG//AD 交BC於G 則CG:GD = CE:EA = 1:1 故 CG:GD:BD = 1:1:1 因為FD//EG FD:EG = BD:BG = 1:2 EG//AD => EG:AD = 2:4 AF:FD = 3:1 Mer 8個月以前 因為AF:FD = 3:1 可設 △AFB = 3x,△BDF = x BF:FE = BD:DG = 1:1 故△AEF = △AFB = 3x △BDF : △AEF = 1:3 留言
因為AF:FD = 3:1
可設 △AFB = 3x,△BDF = x
BF:FE = BD:DG = 1:1
故△AEF = △AFB = 3x
△BDF : △AEF = 1:3