解答

做 EG//AD 交BC於G
則CG:GD = CE:EA = 1:1
故 CG:GD:BD = 1:1:1

因為FD//EG
FD:EG = BD:BG = 1:2
EG//AD => EG:AD = 2:4
AF:FD = 3:1

Mer

因為AF:FD = 3:1
可設 △AFB = 3x,△BDF = x
BF:FE = BD:DG = 1:1
故△AEF = △AFB = 3x
△BDF : △AEF = 1:3

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