Mer 10個月以前 (2y-x)=-(x-2y) (x-2y)²(3x+y)-(x-2y)(3x+y)² =(x-2y)(3x+y)[(x-2y)-(3x+y)] =(x-2y)(3x+y)(-2x-3y) =-(x-2y)(3x+y)(2x+3y) 留言