解答

(2y-x)=-(x-2y)

(x-2y)²(3x+y)-(x-2y)(3x+y)²
=(x-2y)(3x+y)[(x-2y)-(3x+y)]
=(x-2y)(3x+y)(-2x-3y)
=-(x-2y)(3x+y)(2x+3y)

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