解答

✨ 最佳解答 ✨

an = 64*(1/2)^n = 2^(6-n)
bn = (an/4)^2 = [2^(4-n)]^2 = 2^(8-2n)
a6 = 2^0 = 1
b6 = 2^(-4) = 1/16

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