Mer 約2年以前 設△ADE = x,DEGF = x/3,FGCB = x/2 △AFG = x+x/3 = 4x/3 △ABC = (4x/3)+(x/2) = 11x/6 DE² : FG² = △ADE : △AFG = x:(4x/3) = 3:4 所以DE : FG = √3:2 FG² : BC² = △AFG : △ABC = 8:11 FG : BC = √8:√11 = (2√2):11 所以DE : FG : BC = √6:(2√2):√11 留言