Question

小魚

為什麼這裡的log1/2是常數🙏

(3)
(1²) f(x) = dog log ₂ √x²+1, $i $ (ll)
f(x) = log dn ³√x²+1, #²f'(1)
(Z)
Kell (1² f(x) = log log ₂ √x²1
=> f(x) = log (log₂ (x²+1)* )
=> + (x) = log ( = · log₂ (x^²+1 ) )
(log ab- loga + log b)
=
„b
=> f(x) = (log + + log (log (x+1))
常式
=> f'(x) = 0 +
1
log₂ (x²+1) · In 10 ) (x²+1 · 1/2) (2X)
37
1
r
f'(1) = (In 10 ) · log ₂
(In 10). log₂_2 7-dn 2
1
f'(1) - (~10) (In²) ( + Inzo
2)
4
.

Answer 1

阿貓

因為log(1/2)=-0.301…，當然是常數，
因為沒有變數x

小魚

謝謝！