✨ คำตอบที่ดีที่สุด ✨
電動勢就是磁通量對時間的微分再乘負號。
所以他給你磁通量的函數，你可以先把他微分之後，加個負號，就會變成電動勢的函數。
接著你根據題目條件令這個電動勢函數的函數值為0，解方程式得到當下的時間t，再將這個t代回原本的磁通量函數，然後就勇敢的選答案吧#（！
Engineering & Technology
มหาวิทยาลัย
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求解！
(
04. 有一個單線圈置於磁場中,已知通過此線圈面的磁通量為中s(t) =tz-21+4(
Wb),則當線圈上瞬間應電動勢為0時,當時的磁通量為多少Wb?
(A)3 ( (B) 1.5 (C) 0
(D) -1.5 (E) – 5
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哦 知道了謝謝