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在網路上找到算式，但是看不懂
. 計算0.1 M 醋酸(Ka = 1.8x10 “)水溶液的 pH 值。
(2)
1.8 x 10-5=X^2/[0.01-X]
X^2+1.8X10^-5X-1.8X0^-7=0
X=4.15X10^-4
pH=3.38
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在網路上找到算式，但是看不懂
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