求助各位！！這題怎麼算

)化學反應式為N2O4(g)=2NO2(g),在TK、VL的密閉容器中達到平衡,此時N2O4之 分解率為 , 平衡系之總壓為Pıatm;當溫度升至2TK,體積仍為VL,N2O4 在該容 器中之分解率為 ,平衡系之總壓為 P2 atm,求為何? 2 P₁₂ 2 (A)/(B)/(C)/(D)/(E) 5 12 Reck 。 130k

請問第9題 a lot of為甚麼是配quite ？

58 複習講義|英語(全) 程度副詞 * 用來強調或說明動詞或形容詞/副詞的程度。 修飾動詞 the 程度副詞 修飾形容詞> 「be動詞後/一般動詞前:almost; only; really; quite 1.I'm only a junior high school student. 2.1 almost forgot about his birthday. 一般動詞後: a lot; so much; very much; well Mrs. Brown misses her son so much. 形容詞前: very; quite; so; too; almost; pretty This dress is quite beautiful. 形容詞後: enough Peter is tall enough to reach the top. 「學霸 養成棧 1. much 常搭配否定詞。 副詞前: very; quite; so; too; almost; pretty 修飾副詞 You did pretty well. 副詞後: enough wud causadine He ran fast enough to win the game. Arab sdto sa I didn't like him much.(我不太喜歡他。) enough 作為「形容詞」修飾名詞時,須置於名詞前;作為「副詞」修飾形容詞、副詞或 般動詞時,須置於其後。 (1) Do we have enough time to finish the work? (我們有足夠的時間完成工作嗎?) dtam ob vilu 1:4 (2) If you stay long enough, you'll get to know my brother. (如果你待得夠久,你會更了解我弟弟。) 會考隨堂做 (A) 6. Don't give up now. We're there. Just hold on for a little while. (A) almost (C) a lot (B) very (D) so C₂ 7. Simon: Why didn't I make it? Did I not work hard Monica: I don't think you did. Sometimes we should look at how hard others are trying (A) quick (C) enough know more about ourselves. (B) well (D) pretty

第三小題 詳解是寫用3/2PV算，我想問為什麼不能用3/2nRT算呢？是我的計算部分有錯誤還是不能用3/2nRT算

700 2. A容器內裝有氦氣(原子量:He=4),其壓力為2atm,體積為1L,溫度27℃; B容器內裝有氖氣(原子量:Ne=20),其壓力為1atm,體積為4L,溫度127℃。 已知理想氣體常數R=8.3J/mol·K;1大氣壓=1.013×10°N/m²。設系統與外界隔 熱,今用一細管連通此兩容器,則平衡時容器內: (1)氣體壓力為多少大氣壓? (2)容器最後溫度為多少℃? He (3) 氣體分子總動能約為多少焦耳? 答 121 IPV=IPV' 2.1+1.4=p1.5 h = pv 个 3m 300k 13) b 12.1 n, n₁ = 300 n2= 1.4 400 ΣART = == InRT' 100 二 15 2. R. 300+ 3. R-400 = 5.R.T' I' 600+1200=571 7' = 360 K = 87° Ne latm 4L 400k AO ΣEK = = nRT 200 (2x2x 8.3 × 300) + (2 × 3 × 813×42) (24.94300)+(74.7x2001 K

該如何求a 需要過程 謝謝🙏

將f(x)=a(x+2)²-5的二次函數圖形,向右平移3單位、向上平移 18 單位後,得到 新的函數圖形 B,已知兩圖形交於點 P(1, k),試選出正確的選項。 (A)圖形A的頂點坐標為(-2,-5) (B) P 是函數圖形B的頂點 (D) a = 2 (0) k = 13 (E) 函數圖形 A與æ軸沒有交點

為何解答說(2.3)在L右半面就能知道是小於

13.設直線L:(k+1)x+2y=3k-2的斜率為正,且點(2,3)在L之右半平面,則k之範圍 為無解。 ① k<-/-- 合 k+120 19.設4(3 m=

藍筆寫的是解答！ 求過程謝謝

6. 坐標平面上兩點(4,1)和(5,13)在直線x-y+1=0的兩側,又(-1,-1)和(-2,-1)在kx-y+1=0的同側, 則k的範圍 ockc1或2<k<号 -7 (4K-1+1)(5k-13+1) <O -) 4k (5k-12) <0 12 =) k<ok <² ²/3 kco (-k+1+1)(52K+1+1)>0 » kk+2)(-2k+2)>0 ⇒ k²2k<l =) kel 的社

例題在坐標平面上,一道光線沿著向量=(5,5)的方向射出,碰到直線L:x-2y=3 後, 16 假設光線依光學原理的性質反射。(即入射角等於反射角),若反射線的前進方向進為v=(p,q)且p、q為整數，則p+q的可能值為何？

進 167 = (3x - 2y =)) | | | | (②8-2g-7)-1330 73 ≤3x-2y-143 ((x-1)² 解 13 9K+3+4K14--6 1BK-13 k=-1 -3+1=-2 - 3-6537-22 23:13k=13 件/ X=3k+1 X=4 X-1 水 -=-2 在坐標平面上,一道光線沿著向量x=(5,5)的方向射出,碰到直線L:x-2y 7th 為v=(p,q)且p、q為整數,則p+q的可能值為何?(多選) (1)-4 (2)-8 (3)4 (4)8 (5)24 。 33K+)-2( 16 假設光線依光學原理的性質反射。(即入射角等於反射角),若反射線的前。 4g-4+1+ 手做設a、b為實 2 b= 答 -20 0 手做 已知直線 3 L上的投 答 y=-2-21 關釵 列題已知 17 L₁

求解‼️‼️

三、計算題:共6分 1. 如右圖,在梯形ABCD中 AD || BC AD=6, BD =9,BC=13.5,試問: (1)△ABD與DCB 是否相似? 解: (2) 解: AB CD " (3)∠ABD和哪一個角的度數相等? 解: AABD APCB ∴∠ABD=CDBCK 13.5 D (4分) (1分) 4. (1分) 剛題目都有看清楚嗎?要小心陷阱噢!

想請問這題的ACDE選項要怎麼判斷（我只知道B不對…

TB (4) W 3/4 +/+ |- VIF B TA "TB + ²/² TA = W W, TH= TB= 3 4/w 3

想問9和13，為什麼一個可以用despite另一個不行

CA (A) to walk (B) walking (C) walks (D) walked ) The man didn't notice his wallet until he came home. (A) stolen (B) stealing (C) steal (D) steals 9. B) William attended the swimming competition 8. cold. (A) although blonde oy (C) in spite of having 10. (A) Monica still feels hungry despite a big breakfast. (A) having eaten (B) has eaten (C) to have eaten (D) had eaten 11. (D) The teacher decided to forgive Hank his rude behavior. (A) because (B) although (C) in addition (D) in spite of 12. (B) Lauren trembled with fear when she heard someone Stoward her in the dark. 13. ( (B) despite the fact that (D) though had B a bad (A) walked (B) walking (C) walks (D) to walk that Alice had been devoted to her company, she got fired last week. (A) Despite (B) Despite the fact (C) Although (D) Though -4 2023/06/05 22:43