1, f(x) = 2x² + 3x − 2 › g(x) = ax² + bx+c
若f(100) = g(102),f(101) = g(103),f(103) = g(105),則
(a¹b¹c)= (2,\}, }}) (2.-5.0)
f(100)-g(102) = 0
f(101) = g(103) = 0
f(103) - g(105) = 0
g(x)=f(x+2)
= 2(x+2) ³+3(x+2) = 2
=2x+bx+8+3x+6-2
= 2X² +11x+12
Ans: a=2 b=-5, c=0
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