求解第二題！ （因為圖片要兩題一起看所以順便拍進來了）

§ 1.1 An Intuitive Introduction to Limits For Exercises 1 and 2, use the graph of the function f to determine whether each statement is true or false. Explain.(從圖形決定極限) 1. O lim f(x)=XX/ x→-3+ lim f(x) = 1. x→2 2. a) lim f(x)=1. x-→-3+ e) lim f(x) does not exist. x →4+ c) lim f(x) = 2. x->2 b) lim x->0 flim f(x) = 3. x-5 d) lim f(x) = 3. x-4 f(x) = 2. Xe) lim f(x) does not exist. x →3 lim f(x) = 2. X→4 S b) lim f(x) = f(0). x->>0 d) lim f(x)=3. x->2* y 4 3 234 y = f(x)

求解釋這一題 看不太懂😭

例題:【反函數】 若f(x) = x²,f:[0,3]→[09],求 f(x)的反函數。 2: To9]→{0.3] 解: f(x) = x 在 [0,3]上為1-1 函數,取f'(x) = x,則有 f(f'(x)) = (√x)} = =x, ∀x∈[0,1] 345 S' (f(x))=√x² = =x,∀x∈[0,0],故f(x) 的反函數為」。 f(x)=xx 2:57/9:52 y X

自動控制 求解

Design a compensator such that the damping ratio < = 0.5 and the undamped natural frequency Wn 2 rad/sec. R(s) + G.(s) Compensator (a) Dominant closed-loop poles? (b) Angle deficiency? (show the diagram) (c) Lead or lag compensator? 1 0.1s+1 1 52 G(s) → C(s)

想請問這題是如何解出來的？ 手寫的圖是我嘗試解的過程，但沒有解出答案，麻煩大家了🫠

21. A metal ion in a weak-field octahedral complex has two more unpaired electrons than the same ion does in a strong-field octahedral complex. Which of the following could the metal ion be? (A) Cr³+ (B)Mn²+ (C)Co²+ (D)Ti²+ (E)Cu²+

求救微積分神人，我完全看不懂這是什麼啊！！！

用導數定義求極限 f'(a) = limf(x) = f(a) x-a 解 解 8.lim √x+1+√√x - I x-0 √√x+1-√√x+1 x-a lim √x+1+ [(√x+1-1) + (√√x-1-1)]/(x-1) x-0 √√x+1+√√√√x+1 x-0 [√√x+1-1) +(√√x+1-1)]/(x-1) g(x)=√√x+1, g'(0)=- h(x)=√√x-1 h'(0) = 59. lim x-1* lim x-1 w√x - wx √√x - √x k(x)=√√√x+1, k'(0) = "√x - √/x_ √√x - √x 3 練習 3.4E 9 r+1 在解特殊型式之極限問題時有其用處。 + ·*. lim √x+1+√√√x −1 2 3 x-0√√√x+1-3√x+1 1 1 2 3 9 x-1 1 m 1 P 1 2₁√√x+1/x = 0 x-1 lim x-1² √√√x – 1 x-1 1 n 9 1 3/(x-1)² Jx=0 1 3√(x + 1)² %r+ "x-1_√x-1 = 1 = 2₁ X- Jx=0 x-1 √x-1 - 1 pq mn = = 5 m -(n-1) 1 1 3 1 -Xm m 1 -XP P 1 1 + lim n Xn 1 -X q 1 √x=1 √x+1= √1-x 3/1-X !

第一張是題目，第二張是答案，請大家看一下我哪裡寫錯了，一直跟答案對不上，如果有人知道如何解，請讓我知道如何求得答案，謝謝

1.1 模擬測驗 環境化學 Environmental Chemistry 9克的純硫酸(H2SO4)加水至0.5升,試求此硫酸溶液的重量百分濃度?體積莫 9x10² 耳濃度?含多少ppm?當量濃度? 0.5 500

想問這兩個式子怎麼知道什麼時候用加的什麼時候用減的啊？

Sidizzo son ei ji povaworl grey line tolera L apapagoslingeri 14.0 V gool sign S qisning nanalintuniendizzo 00 6.00 (+ 21.21. Snus sur le mure on Roomet while keeping it electrically the 4.0 2 es or parallel combinations of 918 b + a oissant 10.0 V sociated with combining resis-mollastunquodh (a) emoved and replaced by a wire qoo circuit.) Because the circuit is his problem is one in which we → I www 6.02 100 9.00 (2 18.00 bus M 2.0 2 abcda: (2) 10.0 V – (6.0 N) Į — (2.0 ₪) I₂ = 0 befcb: - (4.0 N) I2 − 14.0 V + (6.0 M) — 10.0 V = 0 - 1₂ Figure 21.21 (Example 21.4) led in branches. moq as labeled in Figure 21.21.mais12A circuit containing different i svig 19 d od oni bi u bliud tot lo mo battib 210109 26919rw 1+ en slin es (1) 1₁ + 1₂2-1₂ = 01S sugit ni nobı aldı YOU ARE C 15usdwes (2.02) 4₂2 01 Toyons de = L d (3) -24.0 V + (6.0 N) - (4.0 N)₂ = 0lvom snigul grans di anioq gnilise or of am gids de stod bad i mi smo duo d Monosh 10.0 V (6.02), − (2.0 N) (1,₁ + 1₂) = 0 Tom Tom (4) 10.0 V - (8.02) 4₁ 10 0 sob

想問b怎麼求出來的

1+1 說例5 觀念題 已知 lim x->0 Jax+b-2 [解]此為倒果為因之題目!(逆向考法) [√ax+b-2] [√ax+b+2] <法>原式 = lim x->0 求常數 a、b 之值? ax+b-4 xfax+b+2] b+2] x[√√ax+b+ 若此極限要存在,又要等於1,觀察可知需:分子要出現「x」 +8)+(x +(x+8yx 5+2) 項才能與分母之「x」項抵消! ax 得 b=4,再由 lim x→0 x√ax+4+2 = lim x->0 a = √4+2 4 (台聯大) a =1 =1 得 a=4。

這題怎麼算，求求大神，

2. B = A=[²2 3. 324 02 423 4 2-1-1 -13 LI ] 01 (964) 10 07 03 (961351 LILO 10

請問這題的Y hat=.22X+4.75 這個算式 是怎麼算出來的🥹🥹

r-Izxzy N SY b= xxx 5x a=y-bx 有八位學生的成績如下表,試計算其 SSt、SSreg、SSres 再根據所計算的結果求 決定係數及疏離係數。 f = .22X + 4.75 r² = SSreg SSt [學生 測驗一X 測驗二Y = A|B|C|D|E F G H 6 5 3 7 9 7 5 4 1.73 18 9+7+5+4+5+6+7+5 8 Y = = 學生 | A|B|C|D|E|F|G|H| |預測分數Ÿ 6.07 5.85 5.41 6.29 5.63 6.51 6.73 5.41 SSt = Σ(Y-V)² = 9 +1 +1 + 4 + 1 + 0 + 1 + 1 = 18 = SStres = (Y - Y) = 8.58 +1.32 +0.17+5.24+0.40+0.26 + 0.07 + 0.17 = 16.21 SSreg: Σ(Y− 1)² = 0.00 +0.02 +0.35 +0.08 +0.14 +0.26 +0.53 +0.35 = 1.73 = V0.901 = 0.95 |SSres SSt V1-r2: = 0.096 = =6 4 8 - 5 |16.21 18 6 397 3 5