拜託各位會計好手教教新手

21:20 < . Marbletop, Inc. had the following transactions during October: . ● LINE . (0) • 5 Purchased land and a building for $50,000 and $175,000, . 第一次作業題目.docx 3 Purchased $80,000 of equipment, paying 40% in cash and the balance on account. respectively, for $65,000 cash and signed a note for the balance. Paid monthly rent of $2,000. 8 9 Issued stock for $100,000. 10 Provided services on account for $56,000. 15 Purchased $15,000 of equipment on account. 16 Collected $24,000 from customers who had previously purchased inventory on account. 23 Made a payment of $2,000 plus $300 interest on the notes payable. 24 Paid $9,000 on accounts payable. 28 Purchased supplies of $1,200 29 Paid monthly salaries of $3,000 At the beginning of the month, Marbletop had the following account balances: Accounts Payable Accounts Receivable Buildings Capital Stock Cash Land Wages Expense Required: ||| $ 2,000 12,000 51,000 10,000 10,000 105,000 10,000 NA 46+ Notes Payable Rent Expense 0 Retained Earnings Service Revenue Supplies Equipment Interest Expense 1. Journalize the transactions. 2. Post the journal entries using T-accounts for each account. 3. Prepare a trial balance at October 31, 2022. il 04 $ 40,000 8,000 55,000 125,000 1,000 33,000 2,000

各位大神 求解 拜託🙏🆘

CA 梁柱 一截面積是原來的兩倍 22. Two girders are made of the same material. Girder A is twice as long as girder B and Bo DE C B³ has a cross-sectional area that is twice as great. The ratio of the mass density of girder A to the mass density of girder B is: 質量密度 A) 4 B) 2 C) 1 D) 1/2 E) 1/4 29. During a short interval of time the speed v in m/s of an automobile is given by v=at² + bt³, where the time t is in seconds. The units of a and b are respectively: A) m-s²; m-s4 s³/m; s4/m dv=at+bt² B) C) m/s²; m/s³ D) m/s³; m/s4 E) m/s4; m/s5 34. The position y of a particle moving along the y axis depends on the time t according to the equation B) C) D) E) 質固定,体2倍 #%# 40. The coordinate of an object is given as a function of time by x = 7t-31², where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is: A) 5 m/s X₂=0, X₁₂=14-12=2 B) -5 m/s 11 m/s C) D) -11 m/s (2-0)/2=1 E) -14.5 m/s 41. The coordinate of a particle in meters is given by x(t) = 16t-3.01³, where the time t is in seconds. The particle is momentarily at rest at t = A) 0.75 s A y = at -bt². The dimensions of the quantities a and b are respectively: A) L²/T, L³/T2 B) L/T², L²/T C) L/T, L/T² D) L³/T, T²/L E) none of these 1.3 s 5.3 s 7.3 s 9.3 s V(t) = 16-9+² =- [9t²-16) =-(3t+4) 13t-4) =+= 0.75 45. The velocity of an object is given as a function of time by v = 4t-312, where v is in m/s and t is in seconds. Its average velocity over the interval from t=0 to t=2 s: A) is 0 B) is -2 m/s C) is 2 m/s D) is -4 m/s E) cannot be calculated unless the initial position is given 49. A particle moves along the x axis according to the equation x = 61² where x is in meters and t is in seconds. Therefore: E B) C) D) E) A) the acceleration of the particle is 6 m/s² t cannot be negative the particle follows a parabolic path each second the velocity of the particle changes by 9.8 m/s none of the above

1.21謝謝！

-801. complement form and perform the following operations (note that the sum is +10,627 and requires five digits and a sign). (a) (+9,286) + (+801) (c) (-9,286) + (+801) (b) (+9,286) + (-801) (d) (-9,286) + (-801) signed-2's-complement Termissh. Di sdi 101 1.20 Convert decimal +49 and +29 to binary, using the representation and enough digits to accommodate the numbers. Then perform the binary equivalent of (+29) + (−49), (−29) + (+49), and (−29) + (−49). Convert the answers back to deci- mal and verify that they are correct. 1.21) If the numbers (+9,742)10 and (+641)10 are in signed-magnitude format, their sum is (+10,383)10 and requires five digits and a sign. Convert the numbers to signed-10's- complement form and find the following sums: (a) (+9,742) + (+641) (c) (−9,742) + (+641) (b) (+9,742) + (-641) (d) (−9,742) + (−641) 1.22 Convert decimal 9,045 and 337 to both BCD and ASCII codes. For ASCII, an even parity bit is to be appended at the left. (1.23) Represent the unsigned decimal numbers 609 and 516 in BCD, and then show the steps necessary to form their sum.

請問b跟d 🙏

Chan 1.18 Problems Perform subtraction on the given unsigned binary numbers using the 2's complement of the subtrahend. If the result of subtraction is negative, its decimal equivalent is formed by taking the 2s complement of the result and including a minus sign.SE.F (a) 11001 10010 bra (b) 1100 - 111100 (d) 1100011 (c) 10101 - 11011 10001 55 grow rorrorOFFIC 1.19* The following decimal numbers are shown in signed-magnitude form: +9,286 and +801. Convert them to signed-10's-complement form and perform the following operations (note that the sum is +10,627 and requires five digits and a sign). (a) (+9,286) + (+801) id (b) (+9,286) + (−801) (d) (-9,286) + (−801)

請問有人可以幫我解這三題嗎

2. The financial statements in the year 2021 and 2022, for Kosinski AG contains the following condensed information. December 31 2022 2021 Property, plant&equipment €236,500 €150,000 Accumulated depreciation (37,700) (25,000) Long-term investments 0 15.000 Inventory 35,000 42,000 Accounts receivable (net) 43,300 20,300 Cash 30.900 10,200 €303,000 €212,500 Share capital-ordinary €130,000 € 90,000 Retained earnings 70,000 29,000 Long-term notes payable 70,000 50,000 Accounts payable 21,000 17,000 Accrued liabilities 17.000 26,500 €308,000 €212,500 Additional information for 2022 is: 1. Income before income taxes for the year 2022, €98,800. 2. Depreciation on plant assets for the year, €12,700. 3. Sold the long-term investments for €28,000. 4. Paid dividends of €35,000. 5. Purchased machinery costing €26,500, paid cash. 6. Purchased machinery and gave a €60,000 long-term note payable. 7. Paid a €40,000 long-term note payable by issuing ordinary shares. Paid income taxes of €22,800 for 2022. 8. Instructions: 1. Cash generated from operations = € 2. Net cash provided by operating activities = € 3. Net cash provided by investing activities = € 4. Net increase (decrease) in cash = € @ 5. Free Cash Flow = € @ 填空题 (25 分) 159 (請依照醫目中的填空位置依次填寫答案) Ⓒ29,000 54,200 1,500 20,700 -89400

這題看了很久，還是沒有看出個所以然 連題目都看不太懂 求解版上大神🥹

6.4: Problem 2 Previous Problem List Next (1 point) Let D = $(R), where (u, v) = (u2, u + v) and R = [2,9] × [0,8]. Calculate SSoydA. Note: It is not necessary to describe D. SloydA= Preview My Answers Submit Answers

請問學過測驗學或英文很強的大神，我用紫色畫起來的這段話該怎麼翻比較正確

110 95 63 Performance Are Motor Concepts Language Total ite socioeco indings n these TAL-3 itely v eads 89 104 Self-Help 77 88 Social-emotional Self-Help TAL reate esti ifies ess: nor wh 65 Temir Focial-emotional acc ch "F te er 0 H-1510-09 * 3. 5 PAPER+COPY+FAX 雙頭螢光筆 as the Early Screening Profiles, Differential Abilities Scale, and Peabody Picture Vocabulary Test-IV. A recent study favorably evaluates the con struct validity of the DIAL-3 through confirmatory factor analysis (Assel & Anthony, 2009). As noted the instrument was designed to screen for devel opmental delays in three domains: motor abilities, conceptual knowledge, and language competence. An essential feature of the test is that separate scores are reported for each domain. These domains and the 74 fubtests comprising them were rationally precon- derved by the test authors. An important question is whether the 21 subtests “hang together” statistically in a manner that supports the rational grouping into the three domains provided by the test developers, In other words, do the three domains possess a latent reality, or are they merely figments of the imagina- tions of the test developers? Using test results for 1,560 children ages 3 to 6, Assel and Anthony (2009) found an excellent fit between the three domains tra- ditionally reported on the DIAL-3 and three empiri- cally derived domains found through factor analysis, which supports the construct validity of the test. However, these authors did note that Articulation subtest was a poor index of language compe Cotchine subteet

請問這題為何是y到x 感謝

Figure 4-9 sa PRICE (Dollars per ream) sb 1 1 1 QUANTITY (Reams of paper) supply 2. Refer to Figure 4-9. All else equal, an increase in the use of laptop computers for note-taking would cause a move from a. Sb to Sa. b. x to y C. Sa to Sb. d. y to x. # y to X

有點看不懂旁邊的數字ㄜ

Market Equilibrium Price as a Regulator 3.00 Price (dollars Quantity Quantity Shortage (-) demanded supplied or surplus (+) (millions of bars per week) Price (dollars per bar) Surplus of 6 million bars at $2.00 a bar Supply of energy bars per bar) 2.50 0.50 22 O -22 1.00 15 6 -9 2.00 1.50 10 10 0 2.00 7 15 +6 1.50 2.50 5 5 +10 1.00 Demand for energy bars 0.500 If the price is $2.00 a bar, the quantity supplied exceeds the quantity demanded. > A surplus of 6 million bars. O 5 10 15 20 25 Quantity (millions of bars per week) © 2014 Pearson Education

請問有沒有大神會翻成程式碼？ 我看不懂 Sieve algorithm

1.1 What Is an Algorithm? 33 for p 2 to n do A[p] - P for p < 2 to [n] do //see note before pseudocode if A[p]+0 llp hasn't been eliminated on previous passes jr p * P while j < n do A[j]0 //mark element as eliminated j<j+ p I/copy the remaining elements of A to array L of the primes if( 0 for p + 2 to n do if A[p] = 0 L[i] + A[p] iki +1 return L