請問有人會算這題嗎

二、退火處理的低碳鋼鋼板厚度為3mm, 現在利用沖壓模具剪斷一甜甜圈形狀外徑為 15mm,內徑為 5mm 的料件,若荷重-伸長 量圖形如表2所示,請求出低碳鋼鋼板的剪 力強度。 荷重(kg) | 伸長量(mm) 400 800 1200 1600 2000 2400 2800 3200 3600 4000 3800 3000 2800 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 0.52 0.525 0.53(斷裂)

第一張是題目，第二張是答案，請大家看一下我哪裡寫錯了，一直跟答案對不上，如果有人知道如何解，請讓我知道如何求得答案，謝謝

1.1 模擬測驗 環境化學 Environmental Chemistry 9克的純硫酸(H2SO4)加水至0.5升,試求此硫酸溶液的重量百分濃度?體積莫 9x10² 耳濃度?含多少ppm?當量濃度? 0.5 500

求救

The shaft shown in the figure is machined from AISI 1040 CD steel. The shaft rotates at 1600 rpm and is supported in rolling bearings at A and B. The applied forces are Fi 10 kN and F2 = 4 kN. Determine the minimum fatigue factor of safety based on achieving infinite life. If infinite life is not predicted, estimate the number of cycles to failure. Also check for yielding. 30 mm- A 192 mm 40 mm 12 mm 240 mm 192 mm -45 mm F₂ 240 mm All fillets 1.5 mm R. 192 mm 42 mm 72 mm 12 mm B 30 mm

想問這兩個式子怎麼知道什麼時候用加的什麼時候用減的啊？

Sidizzo son ei ji povaworl grey line tolera L apapagoslingeri 14.0 V gool sign S qisning nanalintuniendizzo 00 6.00 (+ 21.21. Snus sur le mure on Roomet while keeping it electrically the 4.0 2 es or parallel combinations of 918 b + a oissant 10.0 V sociated with combining resis-mollastunquodh (a) emoved and replaced by a wire qoo circuit.) Because the circuit is his problem is one in which we → I www 6.02 100 9.00 (2 18.00 bus M 2.0 2 abcda: (2) 10.0 V – (6.0 N) Į — (2.0 ₪) I₂ = 0 befcb: - (4.0 N) I2 − 14.0 V + (6.0 M) — 10.0 V = 0 - 1₂ Figure 21.21 (Example 21.4) led in branches. moq as labeled in Figure 21.21.mais12A circuit containing different i svig 19 d od oni bi u bliud tot lo mo battib 210109 26919rw 1+ en slin es (1) 1₁ + 1₂2-1₂ = 01S sugit ni nobı aldı YOU ARE C 15usdwes (2.02) 4₂2 01 Toyons de = L d (3) -24.0 V + (6.0 N) - (4.0 N)₂ = 0lvom snigul grans di anioq gnilise or of am gids de stod bad i mi smo duo d Monosh 10.0 V (6.02), − (2.0 N) (1,₁ + 1₂) = 0 Tom Tom (4) 10.0 V - (8.02) 4₁ 10 0 sob

有人會這些東西嗎🥹感謝

3. 如下圖為一四連桿機構,Q2Q4為固定桿,Q2A 線段為輸入桿,設反時針方向之角速度 為100 rpm, Q.B線段長40cm,試用圖解法求A、B及C三點之速度大小(C為QB之中點), 繪圖比例1cm=10cm。 9₂ B A 60° 55⁰ 75 cm 460⁰ A, B 30 cm C 40cm La Wi=1nonyienc 4. 向量 長 25 公分,向量長 50 公分,二者之間夾60°,求Aa➔BD線段大小及方向。 25 Aa Bb E 54334 2

小單求救

Problem 4 (20 points) An oil is being pumped inside a long pipe with a diameter of 10 mm at a Reynolds number of 1000. The oil density is 800 kg/m³ and the viscosity is 20 mPa.s. (a) What is the average and maximum velocity in the pipe? (10 points) (b) If the pipe is replaced by a rectangular channel, shown as the figure, please calculate the Reynolds number when the volumetric flow rate (m³/s) is the same as in the pipe. (10 points) 10 mm TO FE ↓ 10 mm

求解🙏🏼

圖 1.3-5 習題 1.3-6 一長的擋土牆用木柱以 30° 斜撐, 並由混凝土墩承塊支承,示於下圖左。木柱間 的間距為3m 等間距。 為了方便分析,牆與支柱理想化地示於下 圖右,牆底與木柱兩端假設為銷接。土壤對牆 的壓力假設為三角形分布,作用於3m長擋土 牆的合力為F = 190 kN。 若各木柱的橫截面為 150 mm × 150 mm 正 方形,則支柱的壓應力o 為何? RO 擋土牆 A 土壤 木柱混凝土 承塊 630° 1.3-6 1.5 m/ B 630° 0.5 m 4.0 m 習題 1.3-7 如圖所示,一小貨車的後擋板支承 一重 W = 900 N 的箱子。後擋板重 W = 270 N,由二纜索支承(僅一纜索顯示於圖中)。纜索 的截面積為 4 = 11 mm²。 (a) 求纜索的張力 T與正向應力。 (b) 若因箱子和後擋板重量導致桿伸長 8 = 0.42 mm,求桿的平均應變。 H = 300 mm 卡 圖 1.3-7 習題 1.3-8 以備檢修 廂重量W 索長度為 = 6.1 m。 AB= 1.3 m A = 77 m (a) 求各段 (b) 求各段 A 014 1.3-8

想請問一下，為什麼把球拋上去的加速度是負的g？(如果是用跟重力相反方向來解釋的話，那為什麼球掉下來的加速度也還是負的g) 拜託跟我解釋一下！謝謝🙏🏻

wicy AP osses a o the air. Fall apply falling Ball effects glected. v = 0 at highest point TWO becomes less positive Aloiteralsos 正 V降低 400. During ascent, a=-g, speed decreases, and velocity y IQU setle sebj vex V增加 a = -g, speed increases, and velocity becomes more negative $1-991² y = 0 do bszzol Boy Beall During ste descent, Houe esileh V 負

大一線性代數 請問這題怎麼解

EX. S = { 1 + 3x+X* ²X², X+2*, -3 +67€ 23, 3+48-28 229 2-48= 3} is a subset of P3, Find a subset of 5 that forms a basis of Spanis).

請問一下這題怎麼算😭好難

Vout - 5 volt D2 +5 vol o Vout D OVORI = Vout == 4.310 v ok suming the diodes are | (b) tions shown in Figure P9.23 D -9.3 大 li (c) WO Do V 12 +7 V o bin 88. I won T08 . 9.24 Sketch the output waveform and the voltage transfer characteristic for the circuit of Figure P9.24. Assume an ideal diode, us (t) = & sin (it), V, = XV, Ri = 812, and R2 = $ 12. 10 4 lo lo mm ogiloc www bools boRi t V. -Vo 15 k12 15 k92 1 vs borbo R2 V 4V V c) (d) bagnozib Figure P9.24 OU 29,22, find the range of Vin 25 Repeat Problem 9.24, using the offset diode model