請問要怎麼把圖一的表格匯入到phpmyadmin裡呢？我結構是設定圖二這樣，也有試過load data infile了是圖三那樣但都錯誤，拜託大家幫我解惑，想了兩天還是沒有頭緒。

WPS Office | typhoon.csv 三 Menu v 白日语 词 5 @C G10 Qfx A A 1 Typhoon 2 南瑪都 3 梅花 4 米雷 5 桑達 6 艾利 7 梅姬 8 凡那比 9 莫蘭蒂 10 南修 11 萊羅克 12 芭瑪 13 莫拉克 14 莫拉菲 15 蓮花 16 薔蜜 17 哈格比 18 辛樂克 K < > > typhoon 十 Date B + Home Insert 20110821 20110726 20110621 20110520 20110506 20101013 20100915 20100906 20100829 20100827 20090928 20090802 20090714 20090617 20080924 20080917 20080908 Page Layout C Longitude Formulas 128 146 134 141.5 128.4 142 129.5 124 125 117.5 145.5 131 131 117 138 143.7 127 Data Latitude Review D View Tools 12 8 10.5 8.5 11.2 12.5 122 19 23 24.5 15 10 19.5 9.5 18 11.5 15.6 15 Q Click to find commands E F Wind Velocity near TW 53 43 28 55 23 48 45 23 18 23 43 40 28 28 53 45 51 T 1 q 幻明回家 150%* A Go Premium. G +0 |---| ▸ || + x H KY

來人啊 快把這題目斬了

2.2 A batch of 100g of Na2SO4 is dissolved in 200g of H2O and the solution is cooled until 100g of Na2SO4:10H20 is crystallized out. Please do a DOF analysis and calculate the composition of the remaining solution. (Na2SO4:10 H20 = 322.2, Na2SO4=142.05) Answer: DOF = 0; Na2SO4 28%, H20 72% =

A 1.75-kN·m torque is applied to the solid cylinder shown. Determine (a) the maximum shearing stress, (b) the percent of the torque carri... 繼續閱讀

50 mm 25 mm 1.75 kN.m

求解程式碼：請問這題為何答案是D呢?

考題(108 中山資管) 20. Given a piece of code below. What is the value of the variable w? for (i = 0; i < 5; ingentina ) for =0; j < 1; i++) W=2; A. 30 B. 32 D. 42 Ans: (D)

計概 師大資工104年轉學考考古題 想請問這題:D

Assuming that no overflow occurs, how many times do we have to apply the arithmetic left shift operation to multiply an integer by 4? (A) 1 (B) 2 (C) 3 (D) 4 參考解答: B

請問要怎麼看圖填出真值表呢 我知道and or not算法 謝謝

9. For the memory shown in Figure 6, and the initial states of all the memory cells are all 0: AA WEI clock D2 D1 DO WE A1 A0Q2 Q1 QO 1 101 0 00 2 001 1 01 3 111 1 10 4 110 lo 01 S 5 111 1 10 B Figure 6

想請問各位大大 我的算法是對的嗎

VER U. 試求圖 EP3.8a 中,立方結晶面的米勒指數。 解 將此平面沿y軸向右平移量單位,如圖 EP3.86 所示,接著把右後下角當成新原 點,新平面和x軸之截距是1個單位長,所以新平面和各軸之截距是(+1, -, c)。 取其倒數後可寫為(1, -, 0),最後取簡單整數比,得到平面米勒指數 (5120)。 z (1/2 - 1 = 3 - 2 子, 新原點 y X 上 Alw (b) (6)

求解如何算第四題共振電路

- o (a)請求出其轉移函數(transfer unction Hol = 。 (b)請求出錯震頻率(resonance frequency) do (c) 請求出|H(o) | = 1/N2的頻率位置。 (d) 請求出頻寬(band width, BW)為何? L HI = Vs ~ (e) 請求出品質因子(quality factor)為何? 4. 一個並聯共振電路的電感值是30uH,電感線圈電阻是 10 歐姆,電容值是40pF, 期頻率響應之頻寬為何? 9 5. 請繪出高通濾波器與帶通濾波器電路,並請單介紹其訊號選擇之原理。 6. 請找出如下圖函數 g(t) = el 的三角傅利葉級數與 指數傅利葉級數。 | 8(t) KN an - -1.5 -1 -0.5 0 0.5 1.5

大一普物 不知道怎麼計算 求解🙏

30. Review. A 7.80-9 bullet moving at 575 m/s strikes the hand of a superhero, causing the hand to move 5.50 cm in the direction of the bullet's velocity before stopping. (a) Use work and energy considerations to find the average force that stops the bullet. (b) Assuming the force is constant, de- termine how much time elapses between the moment the bullet strikes the hand and the moment it stops moving.

［計算機組織］ 請問這題的 b. 小題 不同的 processor 不是影響 CPI 的值嗎 為什麼可以拿 a. 算出來的 CPI 直接套在這題？

1.7 [15] Compilers can have a profound impact on the performance of an application. Assume that for a program, compiler A results in a dynamic instruction count of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a dynamic instruction count of 1.2E9 and an execution time of 1.5 s. a. Find the average CPI for each program given that the processor has a clock cycle time of 1 ns. CPI = cycles per instruction 1.1 x 10 cycles for 1.0 x 10° instructions => CPL = 1.1 1.5 X 109 cycles for 1.2 x 109 instructions => CPI = 1.25 b. Assume the compiled programs run on two different processors. If the execution times on the two processors are the same, how much faster is the clock of the processor running compiler A's code versus the clock of the processor running compiler B's code? Execution time = CPI x IC x Cycle Time CPIA X ICA X CTP1 = CP1g x IC3 x CT22 CT P:/CTP2 = (CPIE x ICB)/(CPIA X ICA) = (1.25 X 1.2 x 10°)/(1.1. X 1.0 x 10°) = 1.36 Cycle time P1 = 1.36 x Cycle time P2 => P1 is 36% slower than P2