自然科學
大學
想問RC circuit 中 charge 跟 discharge 如附圖內的等式是怎麼得出的呢?
思考了一段時間也上網查過了
The sum ofthe potential difference across the capacitor and resistoris away
Constant, so Vc 十 MRg 三委. As charge flows to the Capacitor, the potential difer:
ence across it increases, which means that the Potential difference across及誠
the current through the circuit, must decrease. In this circuit, the current /當
Credyey the charge on the capacitor, and therefore 7 二 十ZO/2/. As the currit
decreases, we expect the Tate at which the capacitor charges also to decrease
When the potential difference across C Teaches 儿, the potential difference acr0S
AR 1s zero: The current Stops flowing, and the charge on the capacitor ha5出
maximum value Oo = Cx,
When 7 = +Z0/dr is used in the loop rule, we find
和
和
人@
廬
0
ll 生 d
L
where O is the instantaneouSs value of the charge on the positive plate of the
tapacitor and 7iS the current through the wire. We note that the current 7is equal
tothe rate at which the charge O is decredszg, therefores了三一d0/d/. The loop
mle becomes 人
人
解答
您的問題解決了嗎?