96d nt” Chemieal EdUUDT LT
人 說 1
ction below ata certam 1
全 同 同 equilibrium ee 說
ii [Ho2] 三 0.0500 TE 、
ipid container are 總
人 2 抽 Ho(g) + 到(tg) 三一 2HF(g) /@巡 > 1 / 1 語全 全胸
: iibri mmIXtUure, 0
2 於 了 人 0.200 mole of Fz is added to this 1 gquilib- thee
2 caJcuJate the'corcentrations 9f a11 gases 1
)。 入 rium is reesfablished- 2 只汪 人
和 沿之
/ (9 1100 K, 及p 0.25 for the following reactlon 1
三入 3 、 一一 所 全生
/4 2SQ23(g) 十 Qz(g) 二二 250O3(9 du Ttbe
選娘 an ial pressures of 502, 人2 te
全 了Cajculate the eduilibrium Partial pressure 人 同
葬 也62人 5O3 produced 自om an initfaL_mixrure In
8 oo 三 Po 王 0.50 atm and Pso, 三 0. 2人
三人 1和 宅及林用 生
” 46. At 22002C 肥 三 0.050 for the reaction
2509 4 2 yy2(9) +O2(g) =二 2NO() 的
What js 和the partial pressure of NO at equilibrtum as 人選
9 suming he N2 and O2 had initial pressures of 0.80 atm 全
// -彈d 0.20 atm, respectively?
@ / 32 5
相/ 和pe )f reactiOn_ we wi study is that having a very 汪
補- 六sma上有value (K<< 1 Solving for equilibrium concen- 一條0說人
frations jm an eduilibrium problem usually requires
many mathematica| operations to be performed. How-
說 和
even the math involved in solving edquilibrium problems 。。
%6 2
Ina
D6909
, for feactions having smal| K values (K << 1) 1s simpli-
527- fied. Whatassumption js made when solving equilibrium 1
Concentrations for reactions having small 太 values? 534 Le
台 戰 Whenever assumptions are made, they must be checked ler
? (吃 hdiry np general the 59 rule> is used to check t
cd 旨
Me Vaudlty of assuming thatx (or 2x, 3x, and so on) is ga
只 sma compared to some number Whenx (or 2x,
and so
1 less than 和
