確認問題 1 次の式を因数分解しなさい。
(1) 2x²+10x+12
M
2(x+5+6)
A
2(x+2)x+3)
(3)5m² 80
2
5(22-16)
=5(x+4xx-4)
(5) Am 8m - 60
F
4Cm7-23-15)
=4km+3x(m-5)
■ (7) 375
=
25
3032-257
= 3(m+5xm-5)
(9) ar²+6ax+5a
=(x²+x+5)
a(x+1)x+5)つ
* 0 rg-4ry—21y
=¥(22-42-21)
1 5
37
¥(x+3xx-7)
*(13) -8x+12x
= X(-82+(2)
X(12+8x12-8%)
*(15) 5am + 5am-10a
= 5a (mtm-2)
=5.0(2m-2)
□(2)542-54-30
- 5 (α-a-6)
23
> 5(a+2Xa-3)
(4) -3x²-6x+24
3(-x²-2018)
3C-x-4x+2)
(6) 2a2+20a +50
2
2002+100+257
2(a+5Xa+5)
(8) 4-4p²
13
1
4(-p2)
4(++pX1-p)
(10) ax²-ay²
= X(X272)
α (X + XXXY)
(12) 2ab2-12ab+ 18a
55
829(6-66+97
20(6+376+37
=
(14) 2xy-98x
=2x(\2-49)
=2x(y+7xy-7)
(16) -4ab4ab +80b
2
4b(a+a+20)
45
46(α+4x+5)