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ページ1:
§ 4.4 Bijective Functions
Def
A function f A→ B
is
called
bijective iff it is
surjective
and
injective.
Ex
Of A B
f(1): := d
2
B
A = {1, 2, 3, 4}
f(2) == 8
3
B = {α, A, 8, 8}
B,
B,
f(3):= B
4
-8
f(4) = 8
•) f: 2 → 2
f(z) =
= 2 +1.
Surjective
:
Let
WEZ
f(w) =
www.
2.
= W.
(Vy 6B: 3 XEA: (x))
(VwEZ:FzEZ: (2, w) Ef.).
(Z=W-1)
injective: Assume f(z) = f(22). ↔ 8₁+1 = 82+| ↔ 2₁ = 82.
=
•) f: R + R.
f(x) = 3x+1.
↑
bijective
Thm
Recull
Let f A B
→>
that f* = {(xx) (x, y) ε f}
Then
f
is bijective
There
exists a 9: BA St.
gof=IA
^
fog= IB.
Rmk
In this
case
g=f".
In
particular,
the function 9 is unique.
ページ2:
Ex Ex 9: Ex • g: B → A g (α) := | gof(1) = g(f(1)) = g(x)= | 9(B) == 3 gof(2) = 9 (f(2)) = 9(8)=2 9(8) : = 2 918)=4 fog (α) = f(g(a)) = f(i)=9. 9 (w) w-l. (F(2)-2+1) go f(z) = g(2+ 1) = (2+1)−1 = 2. fog (2) = f (2-1) = (2-1) +1 =8 g: R R g(y) =: y-l 3 y= 3x+1. < 4-1 = 3x < y-1 = X 3 proof of the Assume f is bijective Set g:= f" g is actually 9 function. wts Vyeb : 3 x A (y, x) Eg proof (x, y) = f (=) f(x) =y. Since ₤ surjective and injective Vy EB: 3! XEA: (x,y) Ef. <) VYEB: 3: KEA: (y, x) Eg_ g is a well-defined function.
ページ3:
Rmk
11
f(x)=y
Let X EA
.
9(y)=x
(VXEA UYEB)
y = f(x).
->
g(f(x)) = g(y) = x.
→ g of =IA.
Similarly, let y EB
Set x = g(y).
fog (y) = f (g(x)) = f(x) = y.
→ fog = IB.
Assume
9:
: B → A with gof = IA
,
fog IB. exists.
wts fis
bijective (injective & surj)
f
is
Surj
Let yεB. Let X:= g(y).
→ f(x) = f(gly)) = fog (y)@y.
: Let X₁, X2 EA.
f is inj
From gof=IA
Assume f(x) = f(x2),
,
we
know
g(f(x)) = x (UX).
g (f(x)) = g(f(x2)).
->
x1 = x2
→ f is injective
.
Bijective Functions = "Renaming"
Ex (Permutation)
"
in
the
sense
of
sets.
S finite set,
then
a
is
called
permutation.
2(1):=2
bijective function 2: S-S
notation
(233)
[231]
e.g.
S = {1, 2, 3} .
0(2):=3
~(3):=1
ページ4:
can have compositions: 1 2 3 23 23 (2 ³ ³ ) - ( 2 1 3 ) = (1 2³) 23
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