ページ1:

OCR失敗: NoMethodError undefined method `first' for nil:NilClass

ページ2:

OCR失敗: NoMethodError undefined method `first' for nil:NilClass

ページ3:

No.
Date:
Bp=0
B2-B1=0
B₂ =
B₁
Mo.12 Mo. 1,
27.02
12
28
=
A
27291
11
a₁
10
3+X
=
10% =
5
15 757
5x =
15
✗
3 cm
→ 3 cm dr kawat 1
76 cm dr kawat 2
4.
B₂
10 cm 30
Bi
0=120°
10 cm
118
60°
12
20 A
10 cm
30A
COS 120 = 1
-
2
Bp = B₁² + B₂² + 2B₁. B₂.coso
y=2.10-5T
Mo. I,
247.107. 20A
B₁ =
4.10,5 T = 2y
271 0.1
Mo.12 24.10.30A
B₂
=
==
=
M2π.92
271.0.1
6.10-5 T = 34
Bp = ((2y)² + (34)² +x.2y. 34 (- ½)
Bp = /4y² + gy² - by ²
12
Bp = √742
Bp
=
4√7 = 2√7.10-5 T
IDU

ページ4:

0000000
No
Date
Kawat Melingkar
a. Pusat
Mo. I
M
|Bp=
2R
R = Jari 2 (m)
⑭ B
ė
B
I=10A
OB
381
arus
TB
I
2
B
Bp =
Mo.]
ap
ATT-10-7.10
2.0.1
= 2π· 10-9 T
b. Sumbu
B5
=
Mo.1.R²
-MR-
203
a= panjang garis pelukis
(m)
I
R
Sumbu
B
SIDU

ページ5:

1.
contoh:
No
Date
9=5
18
BQ
Ja 13 cm
Ip=
A
Bp
4cm
IQ
129
=
A
Mo.]
• Bp (pusat) = 2R
=
πC
B di P = ?
BQ (suntu)
18
2 Art. 10-7. 10
2.(0.03)
12.10-5T
=>
→ Bdi P = Bp+ BQ
2.
1=2A
Bo
2
5cm 1
3.
0 5CM B
Bo = ?
=
1
30.1097
03.104T
Mo.]
2R
.
44
=
Mo.I.R
2
293
34ft. 107. 125 (0,03) 2
2100573
= 18 × 10-5 T
Att. 10-7.21
21009) 4
2πL. 10 T
Bdi P=?
OB
ip
10cm
2=10A
(SIDU

ページ6:

3.
B1
Mo. I
-2p
2
4πC1075
2(0,01)
= 17.10 T
Mo. 1
B₂
4.10.10
=
279
= 2.10 4 T
No.
Date
2π (0,01)
=> Bdlip = Bit B₂
Solenoida
70000007
Bpusat=
Mo. 1. N
Mo. I. N
Bujung = 21
=
1π. 104T+2.109 T = (1+2) 10" T
N = Juml. lilitan
l= panjang solenoida
4.
Toroida
Ret Pa
Ptoroida
(Reffektif)
=
2
Mo. 1.N
B₁ =
Mr.
27. Reff
5.
·Fluks magnet (Q).
(Q) satuan: Wb
B
Q = B.A. COS O
A- luas penampang
A toroida = π. R²
Re-pa
R=
2
(kalau tdk ada ket.
brrti berimpit. C050=
050=1)

ページ7:

Gaya Lorentz
F = B.I.l.sin O
} 1 kawat
F = B.q.v·sine
Lurus
Contoh:
1
= 5A
2cm
V
9 = +20
V =
103 m/s
No.
Date:
·· pangang kawat (m)
9 = muatan (c)
• sudut antara
B11
B19
·V = kecepatan (m/s)
F= B.q.v. sing
Mo.J
F
2.103
Besar F&arah =?
Aturan tangan Gaya Lorentz
(kanan)
·B.
=
2πa
24.10.5
ZTE (0,02)
7
2.103
F
= 0,1 N (ke atas)
9+
I sesuai dibalik
Mo. 11. 12
F=
Mr. 7.
kawat
27.9
sejajar
=
·a jarak antar-
kawat (m)
114
4/2
114
F12
F21
searah tarik menarik

ページ8:

0000
7.
No.
Date:
contoh:
$23.
F21
413
TH
2A
•F21
e
2
=
=
4cm
Mo-11.12
21a
752
4A
4.10.2.4
27 (0.04)
= 4 x 10-5 N
Jari elektron
"
R=
M.V
.
6cm
6A
Hitung gaya lorentz
tiap satuan pan-
Jang pada kawat 2!
F2 = ?
l
• F23 Mo. 12.13
=
=
2πa
241.104.6
277.10.106)
= 8 × 10-5 N
kg
Fz
F23 F21
=
e
e
=4×105N
(ke kiri)
B.9
.
me = 9.10'
9e
V
=
-31-
-19
= 1,6×10 C
kecepatan elektron (m/s)
Bisa Jari" yg lain, disoal diketahui mag nya)
(SIDU