Question

๛ก(ｰ̀ωｰ́ก)

求解🙏第二小題
是用g=10去算出彈開的加速度再除時間嗎
還有順便問一下第一小題是否正確

★1. 如圖,一彈性球以速率5m/s、入射角為370與牆面發生碰撞,碰
撞後速率保持5m/s、反射角為37°彈開。若球與牆接觸時間為
0.4s,則與牆面接觸期間球的:
(1)速度變化量的量值為多少m/s? (5分) 5/3.0
(2)平均加速度的量值為多少m/s²? (5分)16 mac
答:
5m/s
1-72-4-3707
3700
1地面
C
5m/s

Answer 1

Tomato

the change in velocity is the difference between the initial and the final velocity vector.
the average acceleration vector = Δ(velocity vector)/Δt