Answers

看第一輪的兩步驟:
1. (2/3)a,b+(1/3)a
2. (7/9)a+(1/3)b,(2/3)b+(2/9)a

也可以把兩小步當成兩個矩陣,乘起來就得總矩陣:
[1 ⅓] [⅔ 0]. [(7/9) ⅓]
[0 ⅔][⅓ 1] = [(2/9) ⅔]

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