Question

琴羽

途中式と答え教えて欲しいです

(4) (ac+bd)2-(ad+bc)2
→ p.17, 19, 20

Answer 1

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遥輝

a²c²+2abcd+b²d²-(a²d²+2abcd+b²c²)
=a²c²+b²d²-a²d²-b²c²
=a²(c²-d²)-b²(c²-d²)
=(c²-d²)(a²-b²)
=(c+d)(c-d)(a+b)(a-b)