Question

Uki

請問這一題怎麼繼續呢

27
10.若log = a '
25
解
:
log 45 = ba · blog15 =
a logall-logas: Blog 3 - 2log 5 + log 13³3 5²1
25
2 Sub
b = 10945 = 210g 3 + 109 5 = log (3²-5)
log 15 = log 3 + log5 = log (3-5)
Ans:
5b-a
7

Answer 1

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