Question

nessa

diketahui fungsi g(x) = x2-6x dan f(x) = 2-3x, tentukan nilai x jika (gof)(x) = 7

tolong bantu sekalian caranyaa :(​

Answer 1

lettzsi

(gof)(x) = g(f(x))
= g(2-3x)
= (2-3x)^2 - 6(2-3x)
= 9x^2 - 12x + 4 - 12 + 18x
= 9x^2 + 6x - 8
sehingga
9x^2 + 6x - 8 = 7
9x^2 + 6x - 15 = 0
3x^2 + 2x - 5 = 0
(3x+5)(x-1) = 0
1. 3x+5 = 0
3x = -5
x = -5/3
2. x-1 = 0
x = 1
Semoga membantu!

nessa

makasii