Engineering & Technology
Mahasiswa
請問箭頭指的算式誰能提供詳細的過程
怎麼求出0
輩終: 面及巔的積分 Ni
gm 【例題2.14】對於半徑為?
之封閉型球面而言,證明
撬=0
g 解:
# 向外之法向單位向量為避, 3
拓=- 1 呈 讓 Sin 9
豆 三sin 9cos伙十sin 9sin 交, 十cos 免.
信和 插=引二 呈 ,sin39cos%679+23 jsm 2sin 79
十互信 噴選 Sn 9cos 79=0
920
97
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