Question

訪客.

請問這題a為何用DTFT再逆轉換算出來y[n]=0與解答用z轉換結果不同

2.5. A causal linear time-invariant system is described by the difference equation
y[n]-5y[n-1]+6y[n = 2] = 2x[n— 1].
(a) Determine the homogeneous response of the system, i.e., the possible outputs if x[n] =
0 for all n.
(b) Determine the impulse response of the system.
(c) Determine the step response of the system.
==

2.5. (a) The homogeneous difference equation:
Taking the Z-transform,
y[n] 5y[n 1]+6y[n2] = 0
-
-
1-5z+6z² = 0
(1221)(132-1) = 0.
The homogeneous solution is of the form
Yn [n] A1 (2) A₂(3)".

2.5 Causal LTI
Y[=]-5Y(++)+ by(n-2) = 2x [n-1]
(A)求齊性响应u
W
Me
. XT]
F JR) - 5 y [n-1] + (y [n-1]=
FT
√6
+ Tlery [1-sex + being] 11/20
[n] = A
D

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