為什麼答案是D

( 7)38 阿嬤拿出一張空飄宣傳單,說是她小時候躲空襲警報時,在路上撿到的。大 嘴八舌道,下列四個小朋友的意見哪個最貼切? 約 3. 逐放L貴殿等の自由 人民各位治日本 al ETCARS (A) 魯夫:上面有日文啦!一定是日本人寫來分發的 (B)索隆:單子上「太平洋沿岸兩大國家」是指日本與臺灣 (C)娜美:那是日本「大東亞新秩序」口號的宣傳單 (D) 香吉士:那是盟軍的飛機扔的啦,是對臺灣人喊話! 示厝一排賣(A) 「苑裡高中

求解 我連題目都看不懂😭

35.已知掌機SWETCH 新品體驗展每張門票為200元,若買30張以上(含30張),則可打八折優待; 今阿丁想省錢,故想約朋友一起去看展,則他至少須約x位朋友,就能省到錢。 空中 160 阿丁如計畫約到x位朋友,並買了30張票;給每人一張票並收錢後(每張票價為總金額除以總人 數),剩下來的票全部給阿丁賣,所得的錢全歸阿丁。若阿丁每張以 150 元賣出,且全部賣完,則阿丁 扣除自己買一張票的錢後,可賺多少元? (A)760元 (B)558元 (C)376元 (D)184元 類補材 p.190

幫我畫出正確答案

4. The cross-linking reaction of polyvinyl alcohol forms four water molecules for every B(OH)4 that cross- links two polymer chains. Given the sections of polyvinyl alcohol chains below, sketch how B(OH)4 cross-links the chains. Through what atom chain linkages are the C-C polymer backbones connected? CH CH₂ H O-H O-H H H CH₂ H-O. +B (OH)4 H H CH₂

不知道怎麼畫 教教我吧 謝謝🙏

8. Sketch the graph of a function y = f(x) that satisfies the following con- ver: ditions: f(0) = 0, lim f(x) = 0, lim f(x) = lim f(x) = ∞ xx x-1- x-1+ lim f(x) = lim f(x) = =-〇〇 x-1+ x-1-

問這題🥹🥹

4.以1,2,4,6,9等五個數不可重複排成一個五位數,將這些五位數由小排到大 (如12469,12496,......)後,則第50個數為4129 (8分) 解: 萬為11 萬千百 十个 124 2469 12496 126 49 12694 14269 14 9 h 數學(2)-73 基隆高中

想問C選項 為什麼OA垂直X軸sinθ=0

1.坐標平面上,原點(0,0),(sin(180°-0),cos(180° + 0)),試選出正確的選項。 sing etcoso ACRE OA 的長度為1 M線段 OA cost (B)直線 O4 的斜率為 tan 0 - sint 括OF 垂直 x軸,則 0 = 90°+180°k,k為整數若A LA SHROF ①若A在第二象限,則為第三象限角 - 十 - 浩4在第三象限,則因為第四象限角 AVATAR -0 則sing=0? 980°+360°k180°+360°k,k為整數

請問為什麼是Penthouse 而不是Loft呢？謝謝！

Welcome to Puss' Pet Hotel, world-class cat accommodation in the Dreamvalley metropolitan area. Our guests benefit from trusted and professional care. Our qualified staff have exceptional skills, knowledge and a genuine love of cats. Your pet's safety, comfort and wellbeing are our highest priority. Cat Boarding We know that cats can be a little precious about their living arrangements and require absolute purrfection. That's why Puss' Pet Hotel offers two types of climate-controlled, spacious, clean and comfortable cat accommodation. Our Loft Condo offers a private litter box and secluded sleeping area with soothing music to ensure your special feline enjoys cozy comfort and privacy. Our Penthouse Condo offers two-story accommodation, providing your distinguished kitty with plenty of room to stretch out and explore its home-away-from-home. Loft Condo Penthouse Condo Standard Nightly Rates $20 / night, with each additional cat sharing the same condo costing an additional $5 / night $30/night, with each additional cat sharing the same condo costing an additional $10/night We offer a 20% discount for pets boarding ten plus nights at our hotel. (D) Smuage will rest in www vy vuiti cats 38. Please look at the calendar below. Alex's two cats will stay in the hotel in the coming month. They will check in on Oct. 8 and leave on the morning of Oct. 19. Alex wants to settle his two cats in one condo, but also wants to give them separate space. Which condo is he most likely to choose and how much is the boarding fee? (A) Loft, $220. (B Loft, $275. (C) Penthouse, $352.) Penthouse, $440. Oct. Wed. 275 ros 8p Sun. 3 ✓ 10 17 24 31 Mon. Tue. 4 ✓ 11 18 25 5 √12 19 26 Thu. Fri. 1 7 V8 V15 22 29 6 v 13 √14 20 27 41128 Sat. 2 9 N16 23 30 V

鹼性不是非金嗎？？ 順便 我還是不會分辨an

作用 金 JUSTETCAT PUXU. 鉑､鈀､銠等貴金屬常作為汽車觸媒轉化器中之催化 劑,可將排氣中的有害物質,如烴類､CO 及氮氧化物 等,轉變為 COHO及N,等。 範例 2-5 素養題 電石是一種灰黑色的固態物質,外觀像石頭,硬度大但可被鐵鎚敲碎。若將電石投入 水中會生成一種可燃性的氣體,而水溶液則呈強鹼性。根據上述性質描述,判斷電石 應屬於下列哪種物質? (A)離子化合物 (B)分子化合物 (C)共價網狀固體 (D)金屬元素 (E)合金 非金金 解答根據敘述,電石不具有延性與展性,與水反應後呈強鹼性,顯示其含金屬氫氧 化物,故電石中必含有金屬,應屬於離子化合物。 故選(A) 練習題 2-5 下列有關離子晶體和金屬晶體的敘述,哪些正確?(多重選擇題) (A)離子晶體和金屬晶體在固態時皆具有導電性 (B)金屬晶體不具延性與展性 (C)離子晶體的熔點一定較金屬晶體為高 (D)離子晶體的導熱性不良 (E)金屬晶體 依靠電子海的自由電子而導電

想請問這題🙏，有點看不懂圖三的公式是從何而來，卡住了

EXAMPLE 21.11 FIELD OF A UNIFORMLY CHARGED DISK A nonconducting disk of radius R has a uniform positive surface charge density o. Find the electric field at a point along the axis of the disk a distance x from its center. Assume that x is positive. SOLUTION IDENTIFY and SET UP: Figure 21.25 shows the situation. We rep- resent the charge distribution as a collection of concentric rings of charge dQ. In Example 21.9 we obtained Eq. (21.8) for the field on the axis of a single uniformly charged ring, so all we need do here is integrate the contributions of our rings. EXECUTE: A typical ring has charge dQ, inner radius r, and outer radius r + dr. Its area is approximately equal to its width dr times its circumference 2πr, or dA = 2πr dr. The charge per unit area is σ = dQ/dA, so the charge of the ring is do = o da = 2πor dr. We use dQ in place of Q in Eq. (21.8), the expression for the field due to a ring that we found in Example 21.9, and replace the ring 21.25 Our sketch for this problem. Idr dQ X P dEx dEx radius a with r. Then the field component dEx at point P due to this ring is 1 2πσrx dr 4π€0 (x² + ²)3/2 SOLUTION Continued

請問E選項怎麼算

BEN )14.鉛蓄電池是汽車在運作時不可或缺的電池,請問關於鉛蓄電池的敘述,下列哪 登入門的離線(0) EBON 些是正確的? 2 (A)放電時,PbO, 為陽極、Pb 為陰極 (B)充電時,PbO, 為正極,Pb 為負極 (C)放電過程中,正極重量增加、負極重量減少 增 (D)充電過程中,硫酸水溶液的濃度降低(AI-N) 10Y (E)在某充電過程中,負極的重量減少了4.8g,則正極的重量減少了3.2 g ĐIETCE EYOND THA CA ĐẦU AN 16.