為什麼[A(org)]=n[An(org)]成立 (第三張圖equation 7.9) 感謝

Experiment 7 Experiment 7 The partition of Organic acid between Water and Organic solvent Objectives Understand the partition of a solute between two immiscible solvents. Introduction A chemical analysis that is performed primarily with the aid of volumetric glassware (e.g., pipets, burets, volumetric flasks) is called a volumetric analysis. For a volumetric analysis procedure, a known quantity or a carefully measured amount of one substance reacts with a to-be-determined amount of another substance with the reaction occurring in aqueous solution. The volumes of all solutions are carefully measured with volumetric glassware. The known amount of the substance for an analysis is generally measured and available in two ways: 1. As a primary standard: An accurate mass (and thus, moles) of a solid substance is measured on a balance, dissolved in water, and then reacted with the substance being analyzed. 2. As a standard solution: A measured number of moles of substance is present in a measured volume of solution - a solution of known concentration, generally expressed as the molar concentration (or molarity) of the substance. A measured volume of the standard solution then reacts with the substance being analyzed. The reaction of the known substance with the substance to be analyzed, occurring in aqueous solution, is generally conducted by a titration procedure. The titration procedure required a buret to dispense a liquid, called the titrant, into a flask containing the analyte. A reaction is complete when stoichiometric amounts of the reacting substances are combined. In a titration this is the stoichiometric point. In this experiment the stoichiometric point for the acid-base titration is detected using a phenolphthalein indicator. Phenolphthalein is colorless in an acidic solution but pink in a basic solution. The point in the titration at which the phenolphthalein changes color is called the endpoint of the indicator. Indicators are selected so that the stoichiometric point in the titration coincides (at approximately the same pH) with the endpoint of the indicator.

圖一 請問一下我畫底線的公式是什麼意思 跟圈起來的比熱為什麼會增加跟減少 圖二 這個ph值是大於7跟小於7嗎

03:16 2.10 4G+ HD KB/s Dato 「100 mol= 8 ①亞佛加厥=6x1075=1med. 10° 粒子拔 gav Jas V ④平均原子量 * * = 分子量 1x1023 01% / 150 = 16amu * {/mol 0=1bg 單位 {{ H=MX1+M2X2+M3X3+...(X1+X2+=1) *原子大小二1010 原子核大小=105. 6%] ow% - 22.4 14.5 "Tamu = 6x1033 g g → Ig =6x1023 'amu amu→ 一个原子 -莫耳原子, 电子質量 湯木森荷 tt 〈陰極射線) ×100% 溶液g. @ CM - 溶質 (mg) g 溶液(L) ppm. 溶液(L) 100g *mol » CMx Vxnmal = wx Maral ㄨ 7溶解度 飽合曲線 1.①同類互法. * NaCl-→吸熱buts不增加 过飽合: ④(6)淺水(四)]放糕( 吸熱↑ ↓ 未飽合 ↑↓ 皆放熱 PT st

請問第一和第五題

(8) (1)圖(一)的B譜線可由圖(二)中哪一代號所表示? (2)圖(二)中R與X之能量比為何? R:4~2 X 2^] 5.有A、B、C三種元素,其在週期表中的相關位置如圖所示。 若A、B、C三種元素原子的電子數總和為104。 A C 1-4 = 3:17 =1:4 B 則(1)若ms以正號為先,則A原子最後1個電子的量子數(n,em, s)為何? (9) (2)寫出C元素的基態電子組態? (10)

想問這題要怎麼寫

g) 式開始到弟幾式結束,可生產最多的氫氣? (A)①(B)②(C)③ ④E)無論到第幾式都無法生成氫氣。 二、混合題或非選擇題 10/甲、乙、丙均為可以燃燒的物質,分子量分別為40、48、60。不同量之甲、乙、丙三物質 分別和氧氣完全燃燒後,其所放出的熱均被25℃、100g的水完全吸收。各物質的質量與 水溫變化如下表: 40 ut 48 60 bu 接汽 物質種類 甲 甲 乙 乙 丙 物質質量(g) 10 5 16 8 20 丙 10 氣充 水溫變化(°C) 12 6 16 8 60 X 回答下列(1)、(2)題: :62 ? BC)下列敘述何者正確?(應選3項) * = * D.(A)上述反應為吸熱反應(B)上表中的X值為30 (C)反應所產生之能量大小和物質種類有 關((D)每克物質所產生之能量大小為丙>>乙(E)將水之起始溫度改為35°C,則個別 水溫之上升量會明顯不同。. (2)1mol甲完全燃燒後所放出的熱量為多少cal? 48ra 歷屆試題觀摩, J:12. 1. 有一暖暖包內含100mL水,暖暖包中另有一塑膠袋子,裝有40g氯化鈣。使用時 微用力敲打暖暖包,使其中之塑膠袋破裂,讓水與氯化鈣混合。已知氯化鈣的溶解 為-82.8 kJ/mol,而水的比熱為4.20J/g°C。假設氯化鈣的比熱甚小可以忽略,而 化鈣溶解所釋出的熱量,完全由100mL水所吸收。若在阿里山上,取出一個5°0 暖暖包打開使用,該暖暖包的溫度最高可升到幾°C?(原子量:Cl=35.5,Ca=

求解

3. 取一莫耳 NO2在1atm,327℃時,使其達到分解平衡(2NO2→2NO Oz),今測得混合氣體比重為同狀況下H2之20倍,則NO2 有多少mol 被分解? 12-11 CF02) (3) (4) (A) (A)0.2 (B)0.3 (C)0.4 (D)0.5。作水會基乙部附料

求解紅色圈起來的，緊急😱🙇🙇🙇

OD (A)0.17M (B)1.7M (C)0.14M (D) 1.4 M 設硫酸鈉完全解離) Na2S037=3 DEE 壓 6 啊) CHA U形管 APR 兩邊,兩邊管徑與形狀相同,中間以半透膜分離,半透膜只有水分子能通過,若於375% A中倒入50毫升 2.0M BaCl 水溶液,試問B中應倒ん多少毫升1.0M之NaCl 水溶液,才能使 A、B兩邊平衡後,液面的高度相同? (A) 150 (B) 100 (C) 50 (D) 25 Cox 2x3=1x2x VB 2X3-1X2XV )若0.1M NaC永溶液中,NaCl 的解離度為70%,則該溶液中所含粒子的總濃度為: T= 1.7 17×0.1 = 0.17M UB=150 # 已知水在25℃的蒸氣壓為24mmHg,試求1m硫酸鈉水溶液在25℃時的蒸氣壓約為多少mmHg?(假 知兀xni10 FAQ B (A)21 (B)22 (C)23 (D)24 37=3 甲、乙、丙三個相同試管分別加入2毫升0.10m硫酸鈉、氯化鈉、尿素水溶液。將此三試管直立置 於一密閉的容器內,待其達成平衡後,三試管中溶液的相對高度比較,下列何者正確? NACO Nacl 7-2 12.46

想問一下這題要怎麼列式？

5.在0℃、1atm下,100mL水可溶解純氧 5.6 mL。現於0°C時,將1atm 空 (氣與定量的水長時間接觸,若達溶解平衡時,氧分壓不變,則水中之溶氧量 Appm? Imol STPT 244L 為多少 So₂ = k⋅ Por (A) 8 (B) 16 (B) 16 (C) 24 (D) 32 (E) 42. 56 100 5

請問這題要怎麼算呢？謝謝你！！🙇🏻‍♀️

X = 22,4×0 15.血液中的鈣離子濃度稱之為血鈣,血鈣過低會容易抽筋,心律不整或骨折;要測定血液中 鈣離子濃度可經由下列實驗步驟測得:步驟(一):取2毫升人體血液加入草酸鈉(NazCzO), 使其形成草酸鈣(CaCO4)沉澱,將沉澱物過濾後乾燥 Ca*+NazC2O4 CaC2O4+2Na+ 步驟(二):將得到之草酸鈣以硫酸溶液溶解後,加入2×10-6mol 過錳酸根(MnO4)可將草酸 根(CO2)完全反應, 2MnO4+5C2O4 +16H*→2Mn²++10CO2+8HzO 請回答下列問題: #164x/04 (1)在步驟(一)形成多少克的草酸鈣沉澱?(3分) (2)每10毫升中的血液含多少毫克的鈣離子?(原子量:Ca=40,C=12,O=16)(4分) 20

（1）為何要選a（3）怎麼解

10° = 100 19.以下六種0.1M 水溶液會 M1.0,中湖水 HO MOT (a) HCl (b)NaOH (c) CHCOOH (K』=2×10-5) (d) NazHPO」(H3PO4K=7.1×10-3 M,K=6×10-8 M,Ks=4.4×10-3M) NaHSO4(H2SO4K=1.7×10-2 藥買,卡0.2龜島 甲 (e) NaHSO4 (H₂SOK = 1.7 × 102 M) HOOD HOML0OHM 10: ES CHAJ (f) NaCO3(H,CO之Ka=4.4×107M,K2=4.7×10-1M) x10k Kay (1) 若要配製 pH =7.22([H+]=6.0×108)的緩衝溶液,應選用哪二個溶液?並描述如何配製? (2)取50mL(b)和100mL(c)溶液混合,所得溶液的pH為多少? 10-3mol (3) 在上述(2) 溶液加入1mmol 的NaOH,pH 變為多少? (1) da 247 A NaOH + CH3COOH → CH3COONa + H2D 5×10° 50×1030-1 10x103×10 [H] = Ka = 2x105 pH=5-03 54/03 1×10 100=4.7 -57685 5x103 54153 54153

想請教計算方法，目前求得莫爾比但後續處以0.18（化整數）時感覺很怪，題目要求120克pan的經驗式，但我化完整數後光是C+H前兩項的質量就會超過120克了，想請教各位如何計算

C z Hz N O S o f 3.44 Peroxyacylnitrate (PAN) is one of the components of smog. It is a compound of C, H, N, and O. Deter- mine the percent composition of oxygen and the empirical formula from the following percent composition by mass: 19.8 percent C, 2.50 percent H, 11.6 percent N. What is its molecular formula, given that its molar mass is about 120 g?