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118 進口商家豪將某商品的進價加六成作為定價,販賣時再以八折的價格賣出,已知今 天此商品共賣出20件,獲利4200元,則每件商品賣出的價格為多少元?

2.3.6求講解

1. (D) The old lady sat by the fireplace with her cat (D) 2. ( 13. to lying (C) to lie (D) lying ) The fishing boat moved slowly in the water at (B) in (C) for (D) with 3. (B) This castle appears quietly next to her. (A) lay (B) a large net floating behind it. (A) by dragons. (A) to attack (B) to be attacked (C) to have attacked (D) to have been attacked ) In this game, a person with his or her eyes (C) 4. ( has to spin around several times and then try to pin a tail onto a donkey. (A) cover (B) covering (C) covered (D) to cover a serious fight, but no one 5. (B) Before the accident happened, the couple seems knows the details. (A) having had (B) to have had (C) to have (D) was having Do. (a) Dave can't present the graphs and figures because he seems (A) left (B) leaving (C) to leave (D) to have left his laptop at home.

求解

x+4=36 X 12x= 3、 如右圖,已知ABCDE與EFGHI皆為正五邊形,則 ZAJI= =72度。 治 18065-2120 36×3 = 108 AMAZ 16 801< E B H

求解

1. 已知 sin-cos= ,則下列敘述何正確? (3-1)²=+= 5+C-250 8 13 (4-1)²=—=5+1-246 256 √17 (1) sin cos 0= sin0+ cos 0= 9 3 (3) sin³ 0-cos³ 0= 13 27 √√17 (4) sint - cost =±一 (5) sin° A+cos° 0 =± 9 11 27 8 : 9 SC

求解

B x=-12 3、 如右圖,已知ABCDE與EFGHI皆為正五邊形,則 `LAJI=72度。 36 。 18065-2118 36×3 = 108 B 同心 DE G H

求解

隨堂練習 設每一電阻皆為R 1. 圖(一):正四面體任兩點間等效電阻為何? 2. 圖(二):RAB = ? 3. 圖(三):何者正確?(設電池無內電阻) (A)C、D等電位(B)通過A、D的電流(C)E、C間電阻R與EF間 2R 電阻R,兩者所消耗之功率比為1:4(D)EF兩端的電壓與AE兩端 的電壓兩者比為1:1 B E A 圖 圖(二) R 2 Ans: 1. ㄓㄨㄥ 2.ㄓㄨㄥˊ 3. (A)(B)(C) R 4 B D 41

求解5.9.12

A gin -playground. (A)disappointed (B)disappoint (C)disappointing (D)to disappoint 感到失望的 令人失望的 Some people are concerned that once euthanasia is legalized, doctors would not make every effort patients' lives. (A)saving (B)save (C)to save (D)for saving The businessman donated () half of his fortune to charities, was very generous of

求解3、4題

*+4=36-1**** 1*X=3** 3、 如右圖,已知ABCDE與EFGHI皆為正五邊形,則 `LAJI=72度。 185-279 WA?) OF = 36×3 = 108° AAZ 3+ E H OL 4、如右圖,長方形ABCD中,AB=2,AD=6,若宥心將ADA 沿對角線 AC方向對摺至AD',P為AD'與BC的交點,則 BP= B A = A JA HA b Pb D' x7 168

求解

13 == 3√4 :: AG = DE = √5²+12= = 13 5412 3. 如右圖,在正方形 ABCD 內作一正:4号B △AEF,且E、F分別在BC、CD上。 則: (1)若EF=2,則BE= (2)承(1)題,則正方形ABCD 的面積為 《試題結束》 S BxK E 2+√3 2 x²+(x+1)=(2) OB-00 =00. =>2X²+2X-1=0002 x=-22/448 4 4 小区(負不合) 如 i

求解第3、4題

x = 1 3、 如右圖,已知ABCDE與EFGHI皆為正五邊形,則 LAJI=72度。 18065-211S E H AAAZ 36×3 e DE 1 108 8+1- b D 如右圖,長方形ABCD中,AB=2,AD=6,若宥心將AD 沿對角線 AC方向對摺至AD',P為AD'與BC的交點,則 A B Pb 8 BP= 31 SA = 7A CA =JA