綠色螢光筆的不是很了解 1. 為什麼會有5呢？ 2. 為何要加52000

dand 2. (LO 3, 4) On January 1, 2020, Hayslett AG had the following equity accounts. Share Capital-Ordinary (€10 par value, 260,000 shares issued and outstanding) Share Premium-Ordinary Retained Earnings During the year, the following transactions occurred. April 1 May 1 June 1 Aug. 1 31 Dec. 1 Declared a €1.50 cash dividend per share to shareholders of record on April 15, payable May 1. Paid the dividend declared in April. Announced a 2-for-1 share split. Prior to the split, the market price per share was €24. Declared a 10% share dividend to shareholders of record on August 15, distributable August 31. On August 1, the market price of the shares was €10 per share. Issued the shares for the share dividend. Declared a €1.50 per share dividend to shareholders of record on December 15, payable January 5, 2021. Determined that net income for the year was €600,000. 31 Instructions Solution 2. a. Apr. 1 May 1 June 1 Aug. 1 31 Dec. 1 31 1 Cash Dividends (260,000 × €1.50) Dividends Payable Dividends Payable Cash No journal entry needed for share split Share Dividends (52,000* × €10) Ordinary Share Dividends Distributable (52,000 × €5) Share Premium-Ordinary (52,000 × €5) *520,000 x.10 Ordinary Share Dividends Distributable Share Capital-Ordinary Cash Dividends (572,000** × €1.50) Dividends Payable **(260,000 × 2) + 52,000 Income Summary €2,600,000 1,500,000 3,200,000 Retained Earnings Retained Earnings Share Dividends Cash Dividends (€390,000+ €858,000) 390,000 390,000 520,000 | 260,000 858,000 600,000 1,768,000 390,000 390,000 260,000 260,000 Prepare dividend ent section. 260,000 858,000 600,000 520,000 1.248,000 14. Luz (a) r equ 15. pre 16- 17 for 18

求解b小題🙇

9. In Section 9.2.1, we discussed two dependent samples X; and Y; for i = 1,...,n. Suppose o2, and var(Y) = o for all i = 1,...,n. In addition, cov (X, Y) = 0 for ij. Let di = X₁ - Y₁ denote the difference of two samples. that cov(X, Y) = p, var (X₂) = (a) Find the variance of o2 = var(d;). (b) In page 21 of the course slides, we have already provided the formula of S2. Please show that S is an unbiased estimator of o2. That is, E(S²) = 2/1.

求解第3、4題🙏 證明題總是卡住...

3. Let Bo and ₁ denote the least squares estimators of Bo and 3₁. Define SSE = Σ(Yi-Bo- i=1 B₁X₁)². Show that (a) E (SSE) = 0², (b) cov(Y, ₁X) = 0. 4. In Section 10.4, we defined a test statistic where s² = T = VSEZ SSE. In addition, it is known that T~: n-2' (a) Show that (1) can be re-written as 1 tn-2. T = r√n-2 (1) (2) (b) Use Part (a) to test Ho: p = 0 vs H₁ p 0. [Hint: (2) can be regarded as a test statistic under Ho.]

想請教一下第三題～～～～～

SAL pinnotivno letuten sdt tot 550 sco: Dinamik gyolland het ge The Great Wall of China, one of the greatest wonders of the world, was enlisted in the World Heritage by UNESCO in 1987. Just like a gigantic dragon, the Great Wall 1 up and down across deserts, grasslands, mountains and plateaus stretching approximately 6,700 kilometers from east to west of China. With a history of more than € 70⁰ 2000 years, some of the sections of the great wall are now in ruins. Ye Ry M bliziv linsupon Lots of beautiful legends and stories about the Great Wall 2 following along 015 the construction, and since that time these stories have spread around the country. By all the legends entirely 完全 Meng Jiangnu's story is the most famous and widely spread about the Great Wall. It tells of 4 Meng Jiangnu's bitter weeping made a section TENES of the Great Wall collapse, for her husband died from building the Wall. giggoda .abo Behind the story is the cruel system of hard labor during the reign of Emperor Qin Shihuang. 5 Meng Jiangnu, later generations built a temple, called the Temple of Mengjiangnu, at the foot of the Great Wall in which a statue of her is located. Then, Meng Jiangnu's story will be passed down from generation to generation with the Great Wall. C 1 (A) marches 1 (B) lines (C) winds (D) towers 14 1 C (A) faded away 不樂 B) took place (C) burst out (1) passed down. 傳承 (C) for (A) of 在中 2 (D) within idied mi (D) how (D) In case of # 2 4 (A) what 5 (A) In memory of 1. (B) to ) (B) which ES (B) On behalf of that (C) As a result of 因為 Grants Pass, Oregon, is a fairly small town, it offers much to amuse te most nopular tourist attraction. Visitors JRW 代表 相当地 H 禺 ide

各位大神 求解 拜託🙏🆘

CA 梁柱 一截面積是原來的兩倍 22. Two girders are made of the same material. Girder A is twice as long as girder B and Bo DE C B³ has a cross-sectional area that is twice as great. The ratio of the mass density of girder A to the mass density of girder B is: 質量密度 A) 4 B) 2 C) 1 D) 1/2 E) 1/4 29. During a short interval of time the speed v in m/s of an automobile is given by v=at² + bt³, where the time t is in seconds. The units of a and b are respectively: A) m-s²; m-s4 s³/m; s4/m dv=at+bt² B) C) m/s²; m/s³ D) m/s³; m/s4 E) m/s4; m/s5 34. The position y of a particle moving along the y axis depends on the time t according to the equation B) C) D) E) 質固定,体2倍 #%# 40. The coordinate of an object is given as a function of time by x = 7t-31², where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is: A) 5 m/s X₂=0, X₁₂=14-12=2 B) -5 m/s 11 m/s C) D) -11 m/s (2-0)/2=1 E) -14.5 m/s 41. The coordinate of a particle in meters is given by x(t) = 16t-3.01³, where the time t is in seconds. The particle is momentarily at rest at t = A) 0.75 s A y = at -bt². The dimensions of the quantities a and b are respectively: A) L²/T, L³/T2 B) L/T², L²/T C) L/T, L/T² D) L³/T, T²/L E) none of these 1.3 s 5.3 s 7.3 s 9.3 s V(t) = 16-9+² =- [9t²-16) =-(3t+4) 13t-4) =+= 0.75 45. The velocity of an object is given as a function of time by v = 4t-312, where v is in m/s and t is in seconds. Its average velocity over the interval from t=0 to t=2 s: A) is 0 B) is -2 m/s C) is 2 m/s D) is -4 m/s E) cannot be calculated unless the initial position is given 49. A particle moves along the x axis according to the equation x = 61² where x is in meters and t is in seconds. Therefore: E B) C) D) E) A) the acceleration of the particle is 6 m/s² t cannot be negative the particle follows a parabolic path each second the velocity of the particle changes by 9.8 m/s none of the above

正合方程式的問題（工數） 有點毫無頭緒😵‍💫 求解

Section 1.3 Problems 測試是否為正合 In each of Problems 1-5, test the differential equation for exactness. If it is exact in some region R of the plane, find a potential function and a general solution, perhaps implicitly defined, that is valid for that region. If it is not exact on any region, do not attempt a solution. 1. 2y² + yexy + (4xy + xexy + 2y)y' = 0 2. 4xy + 2x + (2x² + 3y²)y' = 0 3. 4xy + 2x²y + (2x² + 3y²)y' = 0 4.2 cos(x+y) - 2x sin(x + y) - 2x sin(x + y)y' = 0 tlsx9 ² +y+ (3y² + x)y' = 0 5.

這個(c)的 inverse reciprocal trigonometric functions 是指什麼？(hahaha)

In a similar manner, one can define the 'arccosine' and 'arctangent' functions by 'restricting the domains'. The following table summarizes the domains and ranges of these inverse functions. Function Domain Range Function f(x) = sin¯¹(x)| (-1,1)|(−½, 3) || f(x) = sec¯¹(x) f(x) = cos ¹(x) [−1,1] f(x) = tan-¹(x) [0, π] Domain Range R (-)|| f(x) = cot-¹(x) x2! [-7,7- XZ1 OY f(x) = csc¯¹(x) 85-1 xs-1 but fuxito Exercise 4. (a) Sketch the graph y = tan-¹(x) (b) From (a), write down lim tan-¹(r) and lim tan-¹(x). x48 8118 (c) Look up the relevant section in the textbook (Stewart), write down the domains and ranges of the 'inverse reciprocal trigonometric functions' on the right hand side of the above table.

A答案，求救

A laser beam of intensity S and cross-sectional area A is completely absorbed by a particle of mass m for a period At. What is the change in speed of the particle? (A) SAAt/mc; (B) SAAt/m; (C) SA/mc; (D) SAAt/c; (E) None.

題目跟解答在講什麼😅

7-65 tert-Butyl esters [RCO₂C(CH3)3] are converted into carboxylic acids (RCO₂H) by reaction with trifluoroacetic acid, a reaction useful in pro- tein synthesis (Section 26-7). Assign E,Z designation to the double bonds of both reactant and product in the following scheme, and explain why there is an apparent change in double-bond stereochemistry: H C-OCH3 C-OCH3 CF3CO2H C=C + H2C=C(CH3)2 H3C C-OC(CH3)3 C-OH 0- H3C

兩次有絲分裂期之間是指？求解這題謝謝～

04 section 1-4 7. 細胞在兩次有絲分裂期之間,不會發生下列哪一個現象?(A)DNA複製 (B)增加細胞質 的胞器數量 (C)染色質緊密纏繞成染色體 (D)增加細胞質的物質含量。 (E)核糖體製造 蛋白質 已